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Allisa [31]
3 years ago
8

A_____consists of two endpoints. Line Segment Plane Line Point

Mathematics
1 answer:
neonofarm [45]3 years ago
7 0
The answer is line segment. :)
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How do i know if a table is linear
umka21 [38]

it is non-linear, because to get 8 to 24 takes 16 but 0 to 8 only takes 8 (i'm not good at explaining)

5 0
3 years ago
Hi can anyone do this for me please do it on a piece of paper
Vsevolod [243]

9514 1404 393

Answer:

  see attached

Step-by-step explanation:

We don't know the drivers' names or when or where they started. We have made the assumption that the second equation pertains to Kylie.

Each line is plotted with the appropriate slope and y-intercept. The slope is the coefficient of x, and represents the "rise" for each unit of "run" to the right.

8 0
3 years ago
G(r)=-(r+11)(r+14) <br><br>what are the zeros &amp; what is the vertex
Nitella [24]

Answer:

The roots (r) or the Zeros ( other name ) = -11 and -14

Step-by-step explanation:

Post in comments if u need step by step and Ill give to u :)

7 0
3 years ago
Find the probability that when a couple has four ​children, at least one of them is a girl. ​(Assume that boys and girls are equ
AveGali [126]

Answer:

0.9375 = 93.75% probability that at least one of the four children is a girl.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

We have the following sample space

In which b means boy, g means girl

b - b - b - b

b - b - b - g

b - b - g - b

b - b - g - g

b - g - b - b

b - g - b - g

b - g - g - b

b - g - g - g

g - b - b - b

g - b - b - g

g - b - g - b

g - b - g - g

g - g - b - b

g - g - b - g

g - g - g - b

g - g - g - g

Total outcomes

There are 16 total outcomes(size of the sample space)

Desired outcomes

Of these outcomes, only 1(b - b - b - b) there is not a girl.

So the number of desired outcomes is 15.

Probability:

P = \frac{15}{16} = 0.9375

0.9375 = 93.75% probability that at least one of the four children is a girl.

7 0
3 years ago
Medicare would like to test the hypothesis that the average monthly rate for one-bedroom assisted-living facility is equal to $3
aliina [53]

Answer:

C) more than the absolute value of the critical value, we can conclude that the average monthly rate for an assisted-living facility is not equal to $3,300.

Step-by-step explanation:

Hello!

Interest hypothesizes is " the average monthly rate for one-bedroom assisted-living facility is equal to $3300" symbolically: μ = 3300

The study variable is:

X: Monthly rate for a one-bedroom assisted-living facility.

Since there is no information about the distribution of the variable, to be able to study the population mean, I'll assume that the variable has a normal distribution.

The hypothesis is:

H₀: μ = 3300

H₁: μ ≠ 3300

α: 0.05

The statistic to use, considering that there is no known population information and the sample size, is a Student t:

t= <u> X[bar] - μ </u> ~t_{n-1}

       S/√n

n= 12

X[bar]= $3690

S= $530

Using the sample data, calculate the statistic value:

t= <u> 3690 - 3300 </u> = 2.549

       530/√12

The rejection region for this test is two-tailed, with critical values:

t_{n-1; \alpha /2} = t_{11; 0.025} = -2.201

t_{n-1;1-\alpha /2} = t_{11; 0.975} = 2.201

The decision rule is:

Reject the null hypothesis if t ≤ -2.201 or if t ≥ 2.201

Not reject the null hypothesis if -2.201 < t < 2.201

Since the calculated value (2.549) is greater than the right critical value (2.201) the decision is to reject the null hypothesis.

With a signification level of 5%, there is enough evidence to reject the null hypothesis. This means that the population mean of the monthly rate for a one-bedroom assisted living facility is different from $3300.

I hope it helps!

7 0
3 years ago
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