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Sloan [31]
2 years ago
6

Solve the following using substitution method

Mathematics
1 answer:
Wewaii [24]2 years ago
6 0

Solution :

2a + 2b = 7    ...1)

4a + 3b = 12   ...2)

In equation, 1)

a = (7 - 2b)/2   ...3)

Putting value of a in equation 2) we get :

4 × (7 - 2b)/2  + 3b = 12

2( 7 - 2b ) + 3b = 12

14 - 4b + 3b = 12

b = 2

Putting value of b in 3) we get :

a = ( 7 - 2×2)/2

a = 3/2 = 1.5

Now,

2x - 3y = 16   ...5)

x + 2y = -6    ...6)

x = -6 - 2y

Putting above value of x in eq 5) , we get :

2( -6 - 2y ) - 3y = 16

-12 - 4y - 3y = 16

7y = -28

y = -4

x = -6 - ( 2× -4 )

x = 2

Hence, this is the required solution.

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5x+5y=-30 find the x and y intercept
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<em>The x and y intercept of 5x + 5y = -30 are (-6, 0) and (0, -6) respectively.</em>

<h2 /><h2>Explanation:</h2>

The Standard Form of the equation of a line is given by:

Ax+By=C \\ \\ A,B,C \ Real \ Constants \ and \ A>0

So:

5x+5y=-30

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FOR Y-INTERCEPT:

Let's \ set: \\ x=0 \\ \\ 5(0)+5y=-30 \\ \\ Isolating \ x: \\ \\ 5y=-30 \\ \\ y=-\frac{30}{5} \\ \\ \boxed{y=-6}

Finally,<em> the x and y intercept of 5x + 5y = -30 are (-6, 0) and (0, -6) respectively.</em>

<h2>Learn more:</h2>

Parallel lines: brainly.com/question/12169569

#LearnWithBrainly

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