A = $ 861.69
Equation:
A = P(1 + rt)
Calculation:
First, converting R percent to r a decimal
r = R/100 = 5.5%/100 = 0.055 per year,
putting time into years for simplicity,
1 quarters ÷ 4 quarters/year = 0.25 years,
then, solving our equation
A = 850(1 + (0.055 × 0.25)) = 861.6875
A = $ 861.69
The total amount accrued, principal plus interest,
from simple interest on a principal of $ 850.00
at a rate of 5.5% per year
for 0.25 years (1 quarters) is $ 861.69.
Right side was multiplied by 6 so you multiply the left side by 6 so 72:6
<h3>
Answer:</h3>
- B. f(x) = 3,000(0.85)^x
- $1566.02
<h3>
Step-by-step explanation:</h3>
Part A
At the end of the year, the value of the computer system is ...
... (beginning value) - 15% · (beginning value) = (beginning value) · (1 - 0.15)
... = 0.85 · (beginning value)
Since the same is true for the next year and the next, the multiplier after x years will be 0.85^x. Then the value after x years is ...
... f(x) = (beginning value) · 0.85^x
The beginning value is given as $3000, so this is ...
... f(x) = 3000·0.85^x
____
Part B
For x=4, this is ...
... f(4) = 3000·0.85^4 = 3000·0.52200625 ≈ 1566.02
The value after 4 years is $1566.02.
The answer is 1,500. You have to multiply 30 and 50.
32.5 % of lab are wireless devices
<em><u>Solution:</u></em>
Given that there was a total of 30 computers and the computer lab is removing 3 broken computers and adding 13 wireless devices
Now we can first find out total number of computers and devices in lab
total number of computers and devices in lab = 30 computers - 3 + 13 wireless devices
total number of computers and devices in lab = 30 - 3 + 13 = 40
So there are 40 computers and wireless devices in lab
<em><u>To find: what percent of the lab are wireless devices</u></em>
So we have to find what percent of 40 is 13
Let "a" be the required percent
a % of 40 = 13
32.5 % of of lab are wireless devices
