Answer:
y = 6
x = 2
Step-by-step explanation:
rearrange the first equation in terms of x
x = (y - 2)/2
substiute x in the second equation
y = -5[(y-2)/2] +16
Now simpilify and solve for y
y = (-5y + 10)/2 +16
y = -5/2y + 5 + 16
y + 5/2y = 5 + 16
3.5y = 21
y = 6
Now substitue y in the first equation to solve for x
x = (6 - 2)/2
x = 2
3: 8h+24 4: 6h+21 5: 15x+45y 6: 44h+12g
7: 7jk first box 12jm second box. 8: 9ab+13a
Basically you just want to multiply the number outside the parentheses to each number inside them.
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In exponential form it is given as, 8⁻³ = 
<u>Step-by-step explanation:</u>
We have to write the given equation in the exponential form, that is in the form of base to the power value.
Given:
log₈ (
) = -3
Here the base is 8.
In the exponential form, it is written as,
base to the power 3 = 512
Here the reciprocal of 512 is given, so,
base to the power -3 = 
So the exponential form is given as, 8⁻³ = 
2+2+9+0+8+1+2+3+4+5+6+7+8+9 is 66