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3 years ago

A soma do quadrado de um numero com seu quintuplo é igual a zero. qual seu numero

Mathematics

1 answer:

UkoKoshka [18]3 years ago

3 0

<span>a resposta é 18. Espero ter ajudado .</span>

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Liam has to fill a hole in the ground that is 24 inches deep. He fills the hole at a rate of 6 inches in 30 minutes. Write a fun

kupik [55]

Answer:

The function that models the depth of the hole in feet over time in hours is $h(t) = 24 - 12\cdot t$ .

Step-by-step explanation:

According to the statement, the variable to be modelled is the depth of the hole, which decreases whereas is filled. Under the assumption that the hole is filled at constant rate, we obtain the following expression:

$h(t) = h_{o}-\frac{\Delta h}{\Delta t}\cdot t$ (1)

Where:

$h(t)$ - Current depth of the hole, measured in inches.

$h_{o}$ - Initial depth of the hole, measured in inches.

$\Delta h$ - Filled level, measured in inches.

$\Delta t$ - Filling time, measured in hours.

$t$ - Time, measured in hours.

If we know that $h_{o} = 24\,in$ , $\Delta h = 6\,in$ and $\Delta t = 0.5\,h$ , then the function that models the depth of the hole is:

$h(t) = 24 - 12\cdot t$

The function that models the depth of the hole in feet over time in hours is $h(t) = 24 - 12\cdot t$ .

6 0

3 years ago

Please help!! Will mark brainliest!!

Alla [95]

Answer:

Step-by-step explanation:

pythagorean theorem

6^2+8^2=d^2

d=10

7 0

2 years ago

What is 15.49 multiplied 1.3

Tems11 [23]

Answer:

20.137

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

The expression x2y - 2xy - 24y can be factored by first factoring out a common factor of y. After the common factor is removed,

svp [43]

The remaining factor of x^2y - 2xy - 24y is (x - 6)(x + 4)

<h3>How to determine the remaining factor?</h3>

The expression is given as:

x^2y - 2xy - 24y

Factor out y from the expression

y(x^2 - 2x - 24)

Expand the equation

y(x^2 + 4x - 6x - 24)

Factorize

y(x - 6)(x + 4)

Hence, the remaining factor of x^2y - 2xy - 24y is (x - 6)(x + 4)

Read more about factored expression at:

brainly.com/question/19386208

#SPJ1

3 0

1 year ago

Please explain how to do this

Helen [10]

9514 1404 393

Answer:

1/2

Step-by-step explanation:

The rules of exponents are helpful.

(a^b)^c = a^(bc)

a^-b = 1/a^b

$25^{\frac{1}{2}}\times10^{-1}=\dfrac{(5^2)^{\frac{1}{2}}}{10^1}=\dfrac{5^{2\cdot\frac{1}{2}}}{10}\\\\=\dfrac{5^1}{10}=\dfrac{5}{10}=\boxed{\dfrac{1}{2}}$

8 0

3 years ago