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2 years ago

8

699,900 rounded to the nearest thousand

2 answers:

Alexxandr [17]2 years ago

4 0

You can’t round 9,900 to the nearest thousand with out having to round the rest up to. So the answer is 700,000. Hope this helped!

ra1l [238]2 years ago

3 0

THE ANSWER IS 700,000

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30 POINTS FOR WHOEVER CAN SOLVE THIS!!

Cloud [144]

The two inequalities formed will be:
One for ticket quantity:
x + y ≤ 600

One for funds generated via tickets:
5x + 7y ≥ 3500

Equating x to 330,
5(330) +7y ≥ 3500
y = 265

Checking if the other inequality holds true:
330 + 265 ≤ 600
595 ≤ 600

This inequality is still true so they can sell 265 tickets on the event day and cover their expenses.

5 0

2 years ago

24x+7=79<br> help? have to get x by itself, right?

andrey2020 [161]

24x + 7=79
subtract 7 from both sides
24x + 7 - 7= 79 - 7
24x= 72
divide both sides by 24
x= 3

CHECK:
24x + 7= 79
24(3) + 7= 79
72 + 7= 79
79= 79

ANSWER: x= 3

Hope this helps! :)

4 0

3 years ago

You must design a closed rectangular box of width w, length l and height h, whose volume is 504 cm3. The sides of the box cost 3

Charra [1.4K]

Answer:

Dimensions will be

Length = 7.23 cm

Width = 7.23 cm

Height = 9.64 cm

Step-by-step explanation:

A closed box has length = l cm

width of the box = w cm

height of the box = h cm

Volume of the rectangular box = lwh

504 = lwh

$h=\frac{504}{lw}$

Sides which involve length and width and height, cost = 3 cents per cm²

Top and bottom of the box costs = 4 cents per cm²

Cost of the sides $C_{s}$ = 3[2(l + w)h] = 6(l + w)h

$C_{s}$ = 3[2(l + w)h]

$C_{s}=6(l+w)(\frac{504}{lw} )$

Cost of the top and the bottom $C_{(t,p)}$ = 4(2lw) = 8lw

Total cost of the box C = $3024\frac{(l+w)}{lw}$ + 8lw

= $3024[\frac{1}{l}+\frac{1}{w}]$ + 8lw

To minimize the cost of the sides

$\frac{dC}{dl}=3024(-l^{-2}+0)+8w=0$

$\frac{3024}{l^{2}}=8w$

$\frac{378}{l^{2}}=w$ ---------(1)

$\frac{dC}{dw}=3024(-w^{-2})+8l=0$

$\frac{3024}{w^{2}}=8l$

$\frac{378}{w^{2}}=l$

$w^{2}=\frac{378}{l}$ -------(2)

Now place the value of w from equation (1) to equation (2)

$(\frac{378}{l^{2}})^{2}=\frac{378}{l}$

$\frac{(378)^{2} }{l^{4}}=\frac{378}{l}$

l³ = 378

l = ∛378 = 7.23 cm

From equation (2)

$w^{2}=\frac{378}{7.23}$

$w^{2}=52.28$

w = 7.23 cm

As lwh = 504 cm³

(7.23)²h = 504

$h=\frac{504}{(7.23)^{2}}$

h = 9.64 cm

6 0

3 years ago

F(x)=(5x+1)(4x−8)(x+6)f, left parenthesis, x, right parenthesis, equals, left parenthesis, 5, x, plus, 1, right parenthesis, lef

andrey2020 [161]

Answer:

$x=-\frac{1}{5} \:or \: x=2 \:or\: x=-6$

Step-by-step explanation:

Given $f(x)=(5x+1)(4x-8)(x+6)$

The zeros of the polynomial function are the point where the function f(x) equals zero.

$f(x)=(5x+1)(4x-8)(x+6)=0$

If abc=0, then a=0 or b=0 or c=0

Therefore:

$(5x+1)(4x-8)(x+6)=0 \:means\\5x+1=0 \:or \: 4x-8=0 \:or\: x+6=0\\5x=-1 \:or \: 4x=8 \:or\: x=-6\\x=-\frac{1}{5} \:or \: x=2 \:or\: x=-6$

6 0

2 years ago

Y is a number such that 6y = 12

nataly862011 [7]

6y = 12
y = 12/6
y = 2

:)

5 0

2 years ago