Answer:
A = 222 units^2
Step-by-step explanation:
To find the area of this trapezoid, first draw an imaginary horizontal line parallel to AD and connecting C with AB (Call this point E). Below this line we have the triangle CEB with hypotenuse 13 units and vertical side (21 - 16) units, or 5 units. Then the width of the entire figure shown can be obtainied using the Pythagorean Theorem:
(5 units)^2 + CE^2 = (13 units)^2, or 25 + CE^2 = 169. Solving this for CE, we get |CE| = 12.
The area of this trapezoid is
A = (average vertical length)(width), which here is:
(21 + 16) units
A = --------------------- * (12 units), which simplifies to:
2
A = (37/2 units)(12 units) = A = 37*6 units = A = 222 units^2
21*10=210
30*7=210
42*5=210
14*15=210
Answer:
40 feet
Step-by-step explanation:
We are given a right isosceles triangle having lengths of two sides 12 feet and 16 feet.
<em>Since, the triangle is an isosceles triangle i.e. two sides of the triangle are equal.</em>
That is, the three sides of the triangle are 12 feet, 12 feet and 16 feet.
We know that, Perimeter of a triangle = Sum of the sides
Thus, Perimeter of the given triangle = 12 + 12 + 16 = 24 + 16 = 40 feet.
Hence, the total length of the fencing needed is 40 feet.
Answer:
3 hours
Step-by-step explanation:
it is $100 for 1 hour right. Ok so forget about the hourly rates. Then you are left with $300. $300 total÷100 per hour = 3 hours.
Answer:
Note that the tangents to the circles at A and B intersect at a point Z on XY by radical center. Then, since∠ZAB=∠ZQA and ∠ZBA=∠ZQB. ∠AZB+∠AQB=∠AZB+∠ZAB+∠ZBA=180°. ∴ZAQB is cyclic.But if O is the center of w, clearly ZAOB is cyclic with diameter ZO, so ∠ZQO is 90° ⇒Q is the mid-point of XY.Then, by Power of a Point, PY· PX = PA · PB = 15 and it is given that PY+PX = 11. Thus,PX=(11±
)/2. So, PQ=
, PQ²=
. Thus, the answer is 61+4=65.
Step-by-step explanation:
