Re-arranging the inequality to find the test points:
![x- \frac{70}{x}\ \textless \ -3 \\ \\ x- \frac{70}{x}+3\ \textless \ 0 \\ \\ \frac{ x^{2} -70+3x}{x}\ \textless \ 0 \\ \\ \frac{(x-7)(x+10)}{x}\ \textless \ 0](https://tex.z-dn.net/?f=x-%20%5Cfrac%7B70%7D%7Bx%7D%5C%20%5Ctextless%20%5C%20-3%20%5C%5C%20%20%5C%5C%20%0A%20x-%20%5Cfrac%7B70%7D%7Bx%7D%2B3%5C%20%5Ctextless%20%5C%200%20%5C%5C%20%20%5C%5C%20%0A%20%5Cfrac%7B%20x%5E%7B2%7D%20-70%2B3x%7D%7Bx%7D%5C%20%5Ctextless%20%5C%200%20%5C%5C%20%20%5C%5C%20%0A%20%5Cfrac%7B%28x-7%29%28x%2B10%29%7D%7Bx%7D%5C%20%5Ctextless%20%5C%200%20%20)
This means, we need to test the inequality for x = -10, x = 0 and x = 7
Since question assumes that x > 0, so we ignore the values less than 0.
So the test points are x = 0 and x = 7
At x = 0 the expression is undefined.
Between x = 0 and x = 7 the value of expression
![\frac{(x-7)(x+10)}{x}](https://tex.z-dn.net/?f=%20%5Cfrac%7B%28x-7%29%28x%2B10%29%7D%7Bx%7D)
is negative. At x = 7 the value of expression is 0. Above x = 7 the value of expression is positive.
So, the solution to the given inequality will be 0 < x < 7.
In Interval notation, the solution can be written as
(0,7)
1/2x-2/5=3/5 (BTW I got 2/5 by reducing 4/10)
1/2x=7/5 (BTW I got 7/5 by moving 2/5 to the other side)
Then do 7/5 times 2 and you get 14/5
14/5
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if it's a mix fraction, then you write 22 1/2. if improper fraction, then write 45/2
Answer:
15.6
Step-by-step explanation:
40% × 39 = 15.6
Hope this helps
The answer is 5.13 in²
Step 1. Calculate the diameter of the circle (d).
Step 2. Calculate the radius of the circle (r).
Step 3. Calculate the area of the circle (A1).
Step 4. Calculate the area of the square (A2).
Step 5. Calculate the difference between two areas (A1 - A2) and divide it by 4 (because there are total 4 segments) to get <span>the area of one segment formed by a square with sides of 6" inscribed in a circle.
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Step 1:
The diameter (d) of the circle is actually the diagonal (D) of the square inscribed in the circle. The diagonal (D) of the square with side a is:
D = a√2 (ratio of 1:1:√2 means side a : side a : diagonal D = 1 : 1 : √2)
If a = 6 in, then D = 6√2 in.
d = D = 6√2 in
Step 2.
The radius (r) of the circle is half of its diameter (d):
r = d/2 = 6√2 / 2 = 3√2 in
Step 3.
The area of the circle (A1) is:
A = π * r²
A = 3.14 * (3√2)² = 3.14 * 3² * (√2)² = 3.14 * 9 * 2 = 56.52 in²
Step 4.
The area of the square (A2) is:
A2 = a²
A2 = 6² = 36 in²
Step 5:
(A1 - A2)/4 = (56.52 - 36)/4 = 20.52/4 = 5.13 in²