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3 years ago

PLEASE HELP

Mathematics

1 answer:

Artist 52 [7]3 years ago

6 0

Answer:

a. 26

Step-by-step explanation:

The formula for depreciation is given as

y = a(1 - r)^t

a = Initial value = $15,500

y = Current value = 1/10 of Initial value = $1,550

r = depreciation rate = 8.5% = 0.085

t = time in years = ?

Hence,

1550 = 15500(1 - 0.085)^t

1550 = 15500(0.915)^t

Divide both sides by 15500

1550/15500 =(0.915)^t

0.1 = (0.915)^t

Take the Logarithm of both sides

log 0.1 = log(0.915)^t

log 0.1 = t log (0.915)

Divide both sides by log 0.915

t = log 0.1/log 0.915

t = 25.920900964 years

Approximately Time t = 26 years

Option a is correct

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Which ordered pair is a solution of the equations y=-5/4x-2

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3 years ago

Rewrite using a single positive exponent. 3-6 -5

yarga [219]

Answer:

$1 \div {3}^{( 30)}$

Step-by-step explanation:

There are exponent rules I posted above that are being used here.

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2 years ago

An engineer is building a bridge that should be able to hold a maximum weight of 1 ton. He builds a model of the bridge that is

MrRissso [65]

Answer:

First blank- 32000 ounces

Second blank- 2000 pounds

Yes the bridge can hold 1 ton.

Step-by-step explanation:

The ratio of the scale of the model to the real bridge = 1:4

The test model shows the model can take 8000 ounces

The real bridge will therefore take 8000 x 4 = 32000 ounces

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6 0

3 years ago

Read 2 more answers

The equation for f and the graph of g are given. How do the period and the amplitude of the functions

trapecia [35]

Answer:

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Step-by-step explanation:

6 0

3 years ago

Use the following image to assist in your answer.<br> a =<br> - 6<br> - 9<br> - 4

vfiekz [6]

Step-by-step explanation:

Pythagoras' theorem for the smallest one :

$c^2 = 4^2 + 6^2$

$c^2 = 16 + 36$

$c^{2}$ = 52

Pythagoras' theorem for the middle one :

$b^{2}$ = $6^{2}$ + $a^{2}$

Pythagoras' theorem for the biggest one :

$(4+a)^2 = c^2 + b^2$

$16 + 8a + a^2 = 52 + b^2$

Using the formula before (for $b^2$ ) it becomes :

$16 + 8a + a^2 = 52 + (6^2 + a^2)$

$16 + 8a + a^2 = 52 + 6^2 + a^2$

$16 + 8a = 52 + 6^2$

16 + 8a = 52 + 36

16+8a = 88

8a = 88-16

8a = 72

$a = \frac{72}{8}$

a = 9

Verifying :

$b^2 = 6^2 + a^2$

$b^2 = 36 + 81$

$b^2 = 117$

$b^{2}$ = 117

The biggest one :

$(4+a)^2 = c^2 + b^2$

$(4+9)^2 = 52 + 117$

$13^2 = 169$

True

8 0

3 years ago