There are 10 seniors in the class, from which 4 should be chosen by the teacher. The order of the chosen students does not matter. This means that we speak of combinations. THe equation for calculating the number of possible combinations is:
C=N!/R!(N-R), where N is the total number of objects and R is the number of objects we select from the N
In our case, N=10, R=4.
C= 10!/4!*6!=10*9*8*7*6!/6!*4*3*2*1=<span>10*9*8*7/24=5040/24=210
There are 210 different ways for the teacher to choose 4 seniors in no particular order.</span>
43% of 166 is 71.38 so it would be 71 to the nearest whole number!
Cost of lack increased by 30%
new cost of lack will be = 100% + 30% = 130%
We are given that new cost = £65
Thus 130% of original cost = 65
100% of original cost = 65 × 100/130 = £50
Thus original price was £50
<span>For "The probability a business major is female" - you're looking for the probability of being female. That the person is a business major is already given. So, P(A|B)
</span>For "The probability a female student is majoring in business" - you're looking for the probability of being majoring in business. That the person is a female is already given. So, P(B|A)
0.89
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