Answer:
a = 0, b = -15
Step-by-step explanation:
Given two complex number Z1=3cispi and z2=5cis(pi/2)
In polar form;
z1 = 3(cospi + isinpi)
z1 = 3(-1+i0)
z1 = -3+0i
Z2 = 5(cospi/2 + isinpi/2)
Z2 = 5(0+i)
Z2 = 0+5i
Z1*Z2 = (-3+0i)(0+5i)
Z1*Z2 = 0 - 15i +0i + 0i²
Z1*Z2 = 0-15i
comparing 0-15i with a + bi;
a = 0 and b = -15
Answer:
Step-by-step explanation:
That should help
Answer:
y=1/4x
Step-by-step explanation:
y=mx+b
m=1/4
so, y=1/4x+b
Now, look at our line's equation so far: . b is what we want, the 1/4 is already set and x and y are just two "free variables" sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the the point (4,1).
So, why not plug in for x the number 4 and for y the number 1? This will allow us to solve for b for the particular line that passes through the point you gave!.
(4,1). y=mx+b or 1=1/4 × 4+b, or solving for b: b=1-(1/4)(4). b=0.
y=1/4x+0
3) 1 yard is 3 feets so 19 yards
4) 1 lb = 16 oz so 104 oz
Answer:
17576000 different possible license plates
Step-by-step explanation:
Note that in the question, repetition is allowed for both the letters and digits.
For the first letter, there are 26 choices to make. For the each of the letters, there are 26 choices for the second letter, and for each of the letters, there are another 26 choices for the third letter.
Therefore, this gives us 26x26x26 = 17576 possible pairs of letters.
For the three numbers, we have ten possibilities for the first digit, ten possibilities for the second digit, and ten possibilities for the third digit.
Therefore, this gives us 10x10x10 =1000 possible numbers.
The combined possibility of the license plates in both three letters and three numbers is 17576 x 1000 = 17576000 different possible license plates.
