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marusya05 [52]
3 years ago
14

Help..!!! Why do i ask so many questions

Mathematics
1 answer:
guapka [62]3 years ago
5 0

Answer:

Hey there!

-4/3-4/5

-20/15-12/15

-32/15

Let me know if this helps :)

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Simplify the expression. Show all of your work. 16 plus 4 cubed times 2 divided by 16
frozen [14]

Answer:

528

Step-by-step explanation:

Question: 16 + 4^{3} * 2 ÷ 16

Work:

4^{3} = 64

2/16 = 0.125

64/0.125 = 512

512 + 16 = 528

4 0
2 years ago
F(x)=3x/x-1<br><br> answer needed
Ray Of Light [21]
Depends on what your answering for, for this i’d assume ur answering for the function which the answer would be 3x/x-1 - f(x) = 0. let me know if it’s something else you are trying to solve for
5 0
3 years ago
If f(x)=4x^3 - 6x^2 + 2x - 5, then f(-2) = ___________
Art [367]

f(x)=4x^3 - 6x^2 + 2x - 5

f(-2)


Replace X with -2:

4(-2)^3 - 6(-2)^2 + 2(-2) - 5 =

Calulate the powers:

4(-8) - 6(4) +(-4) -5=

Multiply:

-32 - 24 -4 -5=

Subtract

-65



7 0
3 years ago
1. Find the remainder if f(x) = 2x³ + 8x² – 5x + 5 is divided by x – 2.​
Hunter-Best [27]

Answer:

The answer to your question is 43

Step-by-step explanation:

                                 

                  2x³  + 8x² - 5x + 5 / x - 2

Process

1.- Use synthetic division

                      2   8    -5    5     2

                           4    24  38                          

                      2  12    19   43

Quotient    2x² + 12x + 19

Remainder     43

4 0
3 years ago
7x^2=9+x what are the values of x<br><br>Will give medal and points
DENIUS [597]
7x² = 9 + x   Subtract x from both sides
7x² - x = 9    Subtract 9 from both sides
7x² - x - 9 = 0   Use the Quadratic Formula

a = 7 , b = -1 , c = -9

x = \frac{-b \pm  \sqrt{b^2 - 4ac} }{2a}   Plug in the a, b, and c values
x = \frac{- (-1) \pm  \sqrt{(-1)^2 - 4(7)(-9)} }{2(7)}   Cancel out the double negative
x = \frac{1 \pm  \sqrt{(-1)^2 - 4(7)(-9)} }{2(7)}   Square -1
x = \frac{1 \pm  \sqrt{1 - 4(7)(-9)} }{2(7)}   Multiply 7 and -9
x = \frac{1 \pm  \sqrt{1 - 4(-63} }{2(7)}   Multiply -4 and -63
x = \frac{1 \pm  \sqrt{1 + 252} }{2(7)}   Multiply 2 and 7
x = \frac{1 \pm  \sqrt{1 + 252} }{14}   Add 1 and 252
x = \frac{1 \pm  \sqrt{253} }{14}   Split up the \pm
x = \left \{ {{ \frac{1 +  \sqrt{253} }{14} } \atop { \frac{1 -  \sqrt{253} }{14} }} \right.
The approximate square root of 253 is <span>15.905973.
</span>x ≈ \left \{ { \frac{1 + 15.905973}{14} } \atop { \frac{1 - 15.905973}{14} }} \right   Add and subtract
x ≈ \left \{ {{ \frac{16.905973}{14} } \atop { \frac{14.905973}{14} }} \right.   Divide
x ≈ \left \{ {{1.2075} \atop {1.0647}} \right.   Round to the nearest hundredth
x ≈ \left \{ {{1.21} \atop {1.06}} \right.

<span>
</span>
7 0
3 years ago
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