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Anestetic [448]
2 years ago
13

M(5,7)is the midpoint of the line segment joining A(3,4) to B.find the coordinates of B.​

Mathematics
2 answers:
nataly862011 [7]2 years ago
6 0
B(7;10)......look at the picture

VARVARA [1.3K]2 years ago
6 0

Answer:

B(5, 7)

Step-by-step explanation:

Midpoint formula is given as

m(5, 7)= (\frac{x_1+x_2}{2} , \frac{y_1+y_2}{2})  ------------(1)

Here

(x_1, y_1)=(3, 4)

Suppose point B is (x_2, y_2)

Substituting value sin equation (1)

(5, 7) = ( \frac{3+x_2}{2} , \frac {4+y_2} {2} )

5 =  \frac{3+x_2}{2} \\7 =   \frac {4+y_2} {2}

x_2 = 7

y_2 = 10

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2 years ago
Bob does 10 miles on his bike every day. If he continues to ride his bike at this pace, how many miles will he go in h days?
pychu [463]

Answer: in how many days?

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7 0
3 years ago
Suppose that a spherical droplet of liquid evaporates at a rate that is proportional to its surface area: where V = volume (mm3
Alex

Answer:

V = 20.2969 mm^3 @ t = 10

r = 1.692 mm @ t = 10

Step-by-step explanation:

The solution to the first order ordinary differential equation:

\frac{dV}{dt} = -kA

Using Euler's method

\frac{dVi}{dt} = -k *4pi*r^2_{i} = -k *4pi*(\frac {3 V_{i} }{4pi})^(2/3)\\ V_{i+1} = V'_{i} *h + V_{i}    \\

Where initial droplet volume is:

V(0) = \frac{4pi}{3} * r(0)^3 =  \frac{4pi}{3} * 2.5^3 = 65.45 mm^3

Hence, the iterative solution will be as next:

  • i = 1, ti = 0, Vi = 65.45

V'_{i}  = -k *4pi*(\frac{3*65.45}{4pi})^(2/3)  = -6.283\\V_{i+1} = 65.45-6.283*0.25 = 63.88

  • i = 2, ti = 0.5, Vi = 63.88

V'_{i}  = -k *4pi*(\frac{3*63.88}{4pi})^(2/3)  = -6.182\\V_{i+1} = 63.88-6.182*0.25 = 62.33

  • i = 3, ti = 1, Vi = 62.33

V'_{i}  = -k *4pi*(\frac{3*62.33}{4pi})^(2/3)  = -6.082\\V_{i+1} = 62.33-6.082*0.25 = 60.813

We compute the next iterations in MATLAB (see attachment)

Volume @ t = 10 is = 20.2969

The droplet radius at t=10 mins

r(10) = (\frac{3*20.2969}{4pi})^(2/3) = 1.692 mm\\

The average change of droplet radius with time is:

Δr/Δt = \frac{r(10) - r(0)}{10-0} = \frac{1.692 - 2.5}{10} = -0.0808 mm/min

The value of the evaporation rate is close the value of k = 0.08 mm/min

Hence, the results are accurate and consistent!

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3 years ago
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