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AlladinOne [14]
3 years ago
6

URGENT HELP NEEDED!!!!!

Mathematics
1 answer:
Alona [7]3 years ago
7 0

Answer:

k

Step-by-step explanation:

You might be interested in
7 x 3/4 in simplest form
Katarina [22]
The answer is <span>7 x 3/4 in simplest form = 21/4</span>
5 0
3 years ago
In 1990, the population of Boston, Massachusetts was 574,283. In 2000, the population was 589,141. What is the percent of change
MrMuchimi

Answer:

Percent of change in population is 2.6%

Step-by-step explanation:

Given population of Boston is 574,283 measured in year 1990.

And population of Boston in year 2000 is 589,141.

We need to find percent of change in population.

So, percent change =\frac{New\ population-Old\ population}{Old\ population}\times100%

Here old population is 574,283 and new population is 589,141

Plugging these value in formula we get,

Percent change =\frac{589,141-574,283}{574,283}\times100\\\\=\frac{14858}{574,283}\times100=0.0258\times100\\\\=2.587

Rounding to nearest tenth 2.6%

8 0
3 years ago
Original Price Percent of Discount Sale Price<br> $ 5% $57
dalvyx [7]

Answer:

Discount:

$2.85

final price

$54.15

Step-by-step explanation:

Discount = Original Price x Discount %/100

Discount = 57 × 5/100

Discount = 57 x 0.05

You save = $2.85

Final Price = Original Price - Discount

Final Price = 57 - 2.85

Final Price = $54.15

8 0
3 years ago
Given the following exponential function, identify whether the change represents
marin [14]

Answer:

its a growth by 51%

6 0
3 years ago
What is the z-score of a newborn who weighs 4,000 g?.
vagabundo [1.1K]

The z-score of the considered newborn having 4,000 g weight is \dfrac{4000 - \mu}{\sigma}

<h3>How to get the z scores?</h3>

If we've got a normal distribution, then we can convert it to standard normal distribution and its values will give us the z score.

If we have

X \sim N(\mu, \sigma)

(X is following normal distribution with mean \mu and standard deviation  \sigma)

then it can be converted to standard normal distribution as

Z = \dfrac{X - \mu}{\sigma}, \\\\Z \sim N(0,1)

(Know the fact that in continuous distribution, probability of a single point is 0, so we can write

P(Z \leq z) = P(Z < z) )

Also, know that if we look for Z = z in z tables, the p value we get is

P(Z \leq z) = \rm p \: value

For the considered case, the statement in the problem is missing the mean weight of the newborn and standard deviation of the data set of weights of newborn.

Thus, for them, we can consider variables in place of their actual values.

Let we have:

  • X = weights of newborns for some considered system (in grams)
  • \mu = mean weight of newborns (in grams)
  • \sigma = standard deviation of the data set of weights of newborns

Then, the z-score for X = 4000 is

z = \dfrac{x - \mu}{\sigma} = \dfrac{4000 - \mu}{\sigma}

Thus, the z-score of the considered newborn having 4,000 g weight is \dfrac{4000 - \mu}{\sigma}

Learn more about z-scores here:

brainly.com/question/13299273

3 0
2 years ago
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