Answer:
51.8 L is the new volume
Explanation:
In the two situations we have this relationship:
P ₁ . V₁ / T₁ = P₂ . V₂ / T₂
Let's convert the temperature to absolute values
T°K = T°C + 273
22.9°C + 273 = 295.9 K
44.5°C + 273 = 317.5 K
Let's convert now, the Torr to atm.
778 Torr . 1 atm / 760 Torr = 1.02 atm
Now we can replace:
3.4 atm . 14.5L / 295.9K = 1.02 atm . V₂ / 317K
(3.4 atm . 14.5L / 295.9K) . 317 K = 1.02 atm . V₂
( (3.4 atm . 14.5L / 295.9K) . 317 K ) / 1.02 atm = V₂ → 51.8 L
P ₁ . V₁ / T₁ = P₂ . V₂ / T₂ is derived from the Ideal Gases Law equation, and it is fulfilled when the moles of a gas, remains constant after the change of T°, pressure and volume.
Correct Answer: option <span>(1) Mn(s)
Reason:
The </span><span>spontaneity of electrochemical cell, depends on the it's Eo value. Electrochemical cells with positve Eo are spontanous and vice-versa.
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In present case, the Eo of half-cell of interest are as follows:
Eo Zn2+/Zn = <span>-0.763v
</span>Eo Mg2+/Mg = 2.37v
Eo Mn2+/Mn = -1.18v
Therefore, Eo cell (with Zn as one of the half-cell) = Eo Zn2+/Zn - Eo Mn2+/Mn
= -0.763 - (-1.18)
= 0.417v
On other hand, Eo cell (with Mg as one of the half-cell) = Eo Mg2+/Zn - Eo Mn2+/Mn
= -2.37 - (-1.18)
= -1.19v
Thus, Mn(s) <span>metal will spontaneously react with Zn2+(aq), but will not spontaneously react with Mg2+(aq)</span>
Answer:
A. Metalloids.
Explanation:
Metalloids. Metalloids, also called semiconductors, are the elements that border the zigzag line on the periodic table.
Sound spreads in the medium in the form of concentric spheres known as wave-fronts.
Now, as each wave-front expands, it moves away from the source of the sound and expands at a wider space. This means that its energy decreases and the sound becomes quieter.
So, overall, as sound spreads in spheres:
1- The energy per wave decreases
2- The amplitude of the wave decreases
3- The sound becomes quieter as the sphere moves further away from the source
Hope this helps :)<span />