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3 years ago

Glycerol boils at a higher temperature than water. What does this indicate about the attractive forces of glycerol?

Chemistry

2 answers:

madam [21]3 years ago

8 0

Answer:

The answer to your question is: They are stronger than those in water.

Explanation:

When a substance is heated, heat is breaking forces among molecules like hydrogen bonds, london forces, van der waals forces, etc, if a substance has a lot of these forces, the boiling point will be higher because more forces must be broken.Then, glycerol must have stronger forces than those of water.

Lana71 [14]3 years ago

6 0

Answer:

The correct answer is: <u><em>"They are stronger than those in water."</em></u>

Explanation:

Intermolecular forces are those that hold the molecules together. Depending on the magnitude of these forces it will cost more or less to separate the molecules. That is what happens with the boiling point. The boiling point is the temperature at which a liquid leaves its state and enters the gaseous state (vapor). Then the intermolecular forces, which are greater in a liquid state with respect to the gaseous state, have to be broken so that the change of state can occur. The higher the intermolecular forces present in the liquid, the boiling point will be higher.

So, since glycerol has a boiling point higher than water, it indicates that the intermolecular forces will be greater, since it takes more temperature and energy to break the force that bonds the molecules.

So <u><em>the correct answer is: "They are stronger than those in water."</em></u>

You might be interested in

A 35.66g sample of copper is heated using 600j of energy. if the original temperature of the copper is 85C what is its final tem

ira [324]

This problem is providing the mass, energy, initial temperature and specific heat of a sample of copper that is required to calculate the final temperature.

Thus, we recall the general heat equation:

$Q=mC(T_f-T_i)\\$

Which has to be solved for the final temperature, $T_f$ as follows:

$T_f=T_i+\frac{Q}{mC}$

Finally, we plug in the numbers to obtain:

$T_f=85\°C+\frac{600J}{35.66g*0.38\frac{J}{g\°C} } \\\\T_f=129.3\°C$

However, this result is not given in the choices.

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8 0

2 years ago

If a reaction occurs, what will be the products of the unbalanced reaction below?Zn(s) + HCl(aq) -->

irakobra [83]

The products will be $ZnCl_2(s) + H_2(g)$

<h3>Chemical reactions</h3>

Zn is higher than hydrogen in the reactivity series. Thus, it will be able to displace hydrogen from the acid.

The equation of the reaction becomes: $Zn(s) + HCl(aq) -- > ZnCl_2 (s) + H_2 (g)$

Hydrogen gas is released as a result. In fact, it is one of the ways of preparing hydrogen gas in the laboratory.

More on chemical reactivity can be found here: brainly.com/question/9621716

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3 0

2 years ago

Calculate the molarity of a solution prepared by diluting 7.0 mL of 4.0 M solution to a volume of 30 mL.

Finger [1]

Considering the definition of dilution, the molarity of a solution prepared by diluting 7.0 mL of 4.0 M solution to a volume of 30 mL is 0.93 mL.

<h3>What is diluion</h3>

First of all, you have to know that when it is desired to prepare a less concentrated solution from a more concentrated one, it is called dilution.

Dilution is the process of reducing the concentration of solute in solution, which is accomplished by simply adding more solvent to the solution at the same amount of solute.

In a dilution the amount of solute does not change, but as more solvent is added, the concentration of the solute decreases, as the volume (and weight) of the solution increases.

A dilution is mathematically expressed as:

Ci×Vi = Cf×Vf

where

Ci: initial concentration
Vi: initial volume
Cf: final concentration
Vf: final volume

<h3>Molarity of the solution in this case</h3>

In this case, you know:

Ci= 4 M
Vi= 7 mL
Cf= ?
Vf= 30 mL

Replacing in the definition of dilution:

4 M× 7 mL= Cf× 30 mL

Solving:

(4 M× 7 mL)÷ 30 mL= Cf

In summary, the molarity of a solution prepared by diluting 7.0 mL of 4.0 M solution to a volume of 30 mL is 0.93 mL.

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8 0

2 years ago

How many grams are in 1.76 x 10^23 atoms of iodine

Mariana [72]

Answer:

$\boxed {\boxed {\sf About \ 37.1 \ grams \ of \ iodine }}$

Explanation:

To convert from atoms to grams, you must first convert atoms to moles, then moles to grams.

1. Convert Atoms to Moles

To convert atoms to grams, Avogadro's number must be used.

$6.022*10^{23}$

This number tells us the number of particles (atoms, molecules, ions, etc.) in 1 mole. In this case, the particles are atoms of iodine.

$\frac{6.022*10^{23} \ atoms \ I }{1 \ mol \ I}$

Multiply the given number of atoms by Avogadro's number.

$1.76*10^{23} \ atoms \ I*\frac{6.022*10^{23} \ atoms \ I }{1 \ mol \ I}$

Flip the fraction so the atoms of iodine will cancel out.

$1.76*10^{23} \ atoms \ I*\frac{ 1 \ mol \ I}{6.022*10^{23} \ atoms \ I}$

$1.76*10^{23}* \frac{1 \ mol \ I}{6.022*10^{23} }$

Multiply so the problem condenses into 1 fraction.

$\frac{1.76*10^{23} \ mol \ I}{6.022*10^{23} }$

$0.2922617071 \ mol \ I$

2. Convert Moles to Grams

Now we must use the molar mass of iodine, which is found on the Periodic Table.

Iodine Molar Mass: 126.9045 g/mol

Use this mass as a fraction.

$\frac{ 126.9045 \ g\ I }{ 1 \ mol \ I}$

Multiply this fraction by the number of moles found above.

$0.2922617071 \ mol \ I*\frac{ 126.9045 \ g\ I }{ 1 \ mol \ I}$

Multiply. The moles of iodine will cancel.

$0.2922617071 *\frac{ 126.9045 \ g\ I }{ 1 }$

The 1 as a denominator is insignificant.

$0.2922617071 *{ 126.9045 \ g\ I }$

$37.08932581 \ g \ I$

3. Round

The original measurement of 1.76*10^23 has 3 significant figures (1, 7, and 6). Therefore we must round our answer to 3 sig figs. For this answer, that is the tenths place.

$37.08932581 \ g \ I$

The 8 in the hundredth place tells us to round the 0 up to a 1.

$\approx 37.1\ g \ I$

There is about <u>37.1 grams of iodine </u>in 1.76*10^23 atoms.

5 0

3 years ago

PLS heLPPP. IM DYINGG

Shkiper50 [21]

Answer:

exothermic

Explanation:

This chemical reaction is an exothermic reaction because heat is liberated into the environment.

In organic chemistry, the reaction is termed a combustion reaction. In such a reaction, a fuel combines with oxygen to produce carbon dioxide and water.

It is an energy transformation from chemical energy to heat energy.

An exothermic reaction is one in which heat is liberated to the surrounding.
The surrounding becomes hotter at the end of the reaction.

In the reaction depicted, heat is liberated.

4 0

3 years ago