<h3>
Answer:</h3>
56.11 g/mol
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Atomic Structure</u>
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
[Compound] KOH
<u>Step 2: Identify</u>
[PT] Molar Mass of K - 39.10 g/mol
[PT] Molar Mass of O - 16.00 g/mol
[PT] Molar Mass of H - 1.01 g/mol
<u>Step 3: Find</u>
39.10 + 16.00 + 1.01 = 56.11 g/mol
The reaction would be Exothermic
Answer:
5 loaves of bread, 5g of yeast
Answer:
Coefficient in front of the
in the balanced equation - 4
Explanation:
The unbalanced reaction is shown below as:-
On the left hand side,
There are 1 nitrogen atom and 3 hydrogen atoms and 3 oxygen atoms
On the right hand side,
There are 1 nitrogen atom and 2 hydrogen atoms and 2 oxygen atoms
Thus,
Right side,
must be multiplied by 6 and
by 4
Left side,
is multiplied by 5 and
by 4 so to balance the whole reaction.
Thus, the balanced reaction is:-
<u>Coefficient in front of the
in the balanced equation - 4</u>