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Alexxx [7]
3 years ago
5

A car can travel 400 miles on 16 gallons of gasoline. How much gasoline will it need to go 275 miles?

Mathematics
1 answer:
olga55 [171]3 years ago
3 0

Answer:

Step-by-step explanation:

400 ÷ 16 = 25.

16 ÷ 16 = 1.

1 gallon = 25 miles.

275 ÷ 25 = 11

In conclusion, the car used 11 gallons for 275 miles.

Hope this helps!

You might be interested in
An accounting professor is notorious for being stingy in giving out good letter grades. In a large section of 140 students in th
Arlecino [84]

Answer:

The 95% confidence interval for the proportion of students that obtain a letter grade of B or better from this professor is (0.2056, 0.3544). The interpretation is that we are 95% sure that the true proportion of students who obtain a letter grade of B or better from this professor is between 0.2056 and 0.3544.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

140 students, so n = 140

B or better are grades of A or B.

5% earn As, 23% earn Bs, so p = 0.05 + 0.23 = 0.28

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.28 - 1.96\sqrt{\frac{0.28*0.72}{140}} = 0.2056

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.28 + 1.96\sqrt{\frac{0.28*0.72}{140}} = 0.3544

The 95% confidence interval for the proportion of students that obtain a letter grade of B or better from this professor is (0.2056, 0.3544). The interpretation is that we are 95% sure that the true proportion of students who obtain a letter grade of B or better from this professor is between 0.2056 and 0.3544.

7 0
3 years ago
, Hayley sold 20 tickets to the school play for a total of $225 early bird tickets were $10 and regular price tickets were $15 w
Lady_Fox [76]

Answer:

15 early tickets were sold and 5 regular tickets were sold.

Step-by-step explanation:

Let x be the number of early bird tickets sold and y be the number of regular tickets sold.

Total number of tickets sold = 20

Thus, we can write the equation,

x + y = 20

Cost of early bird ticket = $10

Cost of regular tickets = $15

Total cost = $225

Thus, we can write the equation,

225 = 10x + 15y

We solve the equation by elimination method by multiplying first equation by 10 and subtracting.

10x + 15y-(10x+10y) = 225 - 200\\5y = 25\\\Rightarrow y=5\\x + 5 = 20\\\Rightarrow x = 15

Thus, 15 early tickets were sold and 5 regular tickets were sold.

5 0
3 years ago
The price of a train ride is $12 it went up by 1/6 what is the new price<br><br><br> Please help
Serggg [28]
Answer::12/6 :))))))$
5 0
4 years ago
I have the answer but can someone explain how to solve this problem? Thanks!
uranmaximum [27]

Answer:

$32

Step-by-step explanation:

27 was how much money Taylor had after buying a salad that was worth 5 dollars.

Money before buying the salad is 27+5 = 32.

4 0
2 years ago
GIVING AWAY 35 POINTS! What is the graph of this function?
mart [117]

Answer:

Im pretty sure its graph A

Step-by-step explanation:

4 0
3 years ago
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