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damaskus [11]
3 years ago
9

3,050 divided by 75 anwser

Mathematics
1 answer:
Agata [3.3K]3 years ago
8 0

Answer:

40.6666666666

Have a good day!

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Please help me ASAP!!! could someone help me do my geometry?
elena-14-01-66 [18.8K]

Answer:

9. m(YZ) = 102°

10. m(JKL) = 192°

11. m<GHF = 75°

Step-by-step explanation:

9. First, find the value of x

4x + 3 = 3x + 15 (inscribed angle that are subtended by the same arc are equal based on the inscribed angle theorem)

Collect like terms

4x - 3x = -3 + 15

x = 12

4x + 3 = ½(m(YZ)) (inscribed angle of a circle = ½ the measure of the intercepted arc)

Plug in the value of x

4(12) + 3 = ½(m(YZ))

48 + 3 = ½(m(YZ))

51 = ½(m(YZ))

Multiply both sides by 2

51*2 = m(YZ)

102 = m(YZ)

m(YZ) = 102°

10. First, find the value of x.

7x + 5 + 6x + 6 = 180° (opposite angles in an inscribed quadrilateral are supplementary)

Add like terms

13x + 11 = 180

13x = 180 - 11

13x = 169

x = 169/13

x = 13

7x + 5 = ½(m(JKL)) (inscribed angle of a circle = ½ the measure of the intercepted arc)

Plug in the value of x

7(13) + 5 = ½(m(JKL))

96 = ½(m(JKL))

Multiply both sides by 2

2*96 = m(JKL)

m(JKL) = 192°

11. First, find x.

5x + 15 = ½(11x + 18) (inscribed angle of a circle = ½ the measure of the intercepted arc)

Multiply both sides by 2

2(5x + 15) = 11x + 18

10x + 30 = 11x + 18

Collect like terms

10x - 11x = -30 + 18

-x = -12

Divide both sides by -1

x = 12

m<GHF = 5x + 15

Plug in the value of x

m<GHF = 5(12) + 15

m<GHF = 60 + 15

m<GHF = 75°

4 0
3 years ago
write three multiplication equations in which the product will have two zeros. use 50 as one of the factors
zysi [14]
50x2=100 50x4=200 50x6=300
7 0
3 years ago
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The product of 2 more than a number and 10 is 36 more than 8 times the numbe. whats the number?​
chubhunter [2.5K]

Answer: 8

Step-by-step explanation:

let x = the number

(x + 2)*10 = 8x + 36

10x + 20 = 8x + 36

2x = 16

x = 8

4 0
3 years ago
Drag and drop each expression into the box to correctly classify it as having a positive or negative product
AfilCa [17]

Following expressions will have negative product

(\frac{1}{2})(-\frac{1}{2})\ and\ (-\frac{1}{2})(\frac{1}{2})

Following expressions will have positive product

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Further explanation:

We will see at each expression one by one

First expression is:

(-\frac{1}{2})(\frac{1}{2})

In the given expression one term is positive and one term is negative. The product of negative and positive terms is negative.

Second Expression is:

(-\frac{1}{2})(-\frac{1}{2})

Both terms are negative and the product of two negative terms is positive.

Third Expression is:

(\frac{1}{2})(-\frac{1}{2})

The expression has one positive and one negative term so the product will be negative

Fourth Expression is:

(\frac{1}{2})(\frac{1}{2})

Both terms are positive so the product will also be positive

Keywords: Product, Expressions

Learn more about expressions at:

  • brainly.com/question/10699220
  • brainly.com/question/10703930

#LearnwithBrainly

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The cosine law
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3 years ago
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