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1 answer:
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Answer:
- 46 seconds
- 6851.5 feet
Step-by-step explanation:
The altitude of each plane can be expressed by an equation that adds the initial altitude and the product of time and its rate of climb.
plane A: y = 4057 +60.75t
plane B: y = 5000 +40.25t
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We want to find the time when their altitudes are the same:
4057 +60.75t = 5000 +40.25t . . . . equate the expressions for y
20.50t = 943 . . . . . . . . . subtract (40.24t +4057)
t = 46 . . . . . . . . . . . . divide by the coefficient of t
At t=46, the altitude of the planes will be ...
y = 5000 +40.25(46) = 5000 +1851.5 = 6851.5
The planes are at the same altitude after 46 seconds.
Both planes will be at an altitude of 6851.5 feet.
