3 years ago

Evaluate ab+bc+ca . If a²+b²+c²=50 and a+b+c=12

Mathematics

2 answers:

Nikitich [7]3 years ago

8 0

Answer:

ab + bc + ca = 47

Step-by-step explanation:

Using the algebraic identity

(a + b + c) = a² + b² + c² + 2(ab + bc + ca) , then

12² = 50 + 2(ab + bc + ca)

144 = 50 + 2(ab + bc + ca) ← subtract 50 from both sides

94 = 2(ab + bc + ca) ← divide both sides by 2

47 = ab + bc + ca

GuDViN [60]3 years ago

5 0

Answer:

ab+bc+ac=47

Step-by-step explanation:

(a+b+c)=12

Square both sides

a^2+b^2+c^2+2(ab+bc+ac)=144

2(ab+bc+ac)=94

ab+bc+ac=47

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3 years ago

Evaluate ab+bc+ca . If a²+b²+c²=50 and a+b+c=12​

Evaluate ab+bc+ca . If a²+b²+c²=50 and a+b+c=12