Evaluate ab+bc+ca . If a²+b²+c²=50 and a+b+c=12
2 answers:
Answer:
ab + bc + ca = 47
Step-by-step explanation:
Using the algebraic identity
(a + b + c) = a² + b² + c² + 2(ab + bc + ca) , then
12² = 50 + 2(ab + bc + ca)
144 = 50 + 2(ab + bc + ca) ← subtract 50 from both sides
94 = 2(ab + bc + ca) ← divide both sides by 2
47 = ab + bc + ca
Answer:
ab+bc+ac=47
Step-by-step explanation:
(a+b+c)=12
Square both sides
a^2+b^2+c^2+2(ab+bc+ac)=144
2(ab+bc+ac)=94
ab+bc+ac=47
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Step-by-step explanat
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