Answer: $5
Step-by-step explanation:
Let the small candy be represented by x.
The medium candy was twice as expensive as the small candy. This will be: = 2×x = 2x
The large candy was $5 more than the medium candy. This will be: = 2x + 5
Since Jason spent a total of $30 on
candy, the cost of the small candy will be:
x + 2x + 2x + 5 = 30
5x + 5 = 30
5x = 30 - 5
5x = 25
x = 25/5
x= 5
The small candy cost $5
If you would like to know the truck's value after 2 years, you can calculate this using the following steps:
8% of 32,500 = 8% * 32,500 = 8/100 * 32,500 = 2,600
32,500 - 2,600 = 29,900
8% of 29,900 = 8% * 29,900 = 8/100 * 29,900 = 2,392
29,900 - 2,392 = 27,508
The correct result would be 27,508.
Answer:
Answer:
WF=34
Step-by-step explanation:
Point I lies between points W and F.
It means point WI + IF = WF
SO WI + IF = WF
=
WF = 15x – 21
WI= 7x-3
IF= 2x+4
WI + IF = WF
7x-3 +2x+4= 15X-21
7x+2x-15x= -21-4+3
-6x = -22
X= -22/6
X= 11/3
So WF = 15x – 21
WI= 7x-3
IF= 2x+4
WI + IF = WF
=
7X-3 +2x+4= 15x-21
7x+2x-15x= -21-4+3
-6x = -22
X= -22/6
X= 11/3
So WF = 15x – 21
WF= 15(11/3) -21
WF= 55-21
WF=34
1. Find the equation of the line AB. For reference, the answer is y=(-2/3)x+2.
2. Derive a formula for the area of the shaded rectange. It is A=xy (where x is the length and y is the height).
3. Replace "y" in A=xy with the formula for y: y= (-2/3)x+2:
A=x[(-2/3)x+2] This is a formula for Area A in terms of x only.
4. Since we want to maximize the shaded area, we take the derivative with respect to x of A=x[(-2/3)x+2] , or, equivalently, A=(-2/3)x^2 + 2x.
This results in (dA/dx) = (-4/3)x + 2.
5. Set this result = to 0 and solve for the critical value:
(dA/dx) = (-4/3)x + 2=0, or (4/3)x=2 This results in x=(3/4)(2)=3/2
6. Verify that this critical value x=3/2 does indeed maximize the area function.
7. Determine the area of the shaded rectangle for x=3/2, using the previously-derived formula A=(-2/3)x^2 + 2x.
The result is the max. area of the shaded rectangle.
Answer:whats the question
Step-by-step explanation: