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notka56 [123]
3 years ago
15

Solve congruent figures ​

Mathematics
1 answer:
Nastasia [14]3 years ago
8 0

Answer:

x=16

Step-by-step explanation:

x+15=6x-65

x+80=6x

   80=5x

    16=x

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29. Which property justifies the statement below?
OleMash [197]

Answer:

d I think is right sorry If it's not

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3 years ago
Use a sum or difference formula to find the exact value of the trigonometric function. sine startfraction 7 pi over 12 endfracti
VARVARA [1.3K]
We have that
<span>sin (7π/12)=?

we know that
</span>7π/12=(π/4+π/3)
and 
<span><span>sin<span>(A+B)</span>=sin<span>(A)</span>cos<span>(B)</span>+cos<span>(A)</span>sin<span>(B)

then
</span></span>sin(π/4+π/3)=sin(π/4)cos(π/3)+cos(π/4)sin(π/3)
sin(π/4+π/3)=(√2/2)(1/2)+(√2/2)(√3/2)-------> (√2/4)+(√6/4)---> (√2+√6)/4

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4 0
3 years ago
Which of the following are true about the correlation coefficient r? Select one or more:
gladu [14]

Answer:

Which is the output of the formula =AND(12>6;6>3;3>9)?

A.

TRUE

B.

FALSE

C.

12

D.

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Step-by-step explanation:

4 0
4 years ago
Read 2 more answers
Suppose that the amount of time T a customer spends in a bank is exponentially distributed with an average of 10 minutes. What i
Bad White [126]

Answer:

The probability that a customer will spend more than 15 minutes total in the bank, given that the customer has already waited over 10 minutes  is 0.6065.

Step-by-step explanation:

The random variable <em>T</em> is defined as the amount of time a customer spends in a bank.

The random variable <em>T</em> is exponentially distributed.

The probability density function of a an exponential random variable is:

f(x)=\lambda e^{-\lambda x};\ x>0

The average time a customer spends in a bank is <em>β</em> = 10 minutes.

Then the parameter of the distribution is:

\lambda=\frac{1}{\beta}=\frac{1}{10}=0.10

An exponential distribution has a memory-less property, i.e the future probabilities are not affected by any past data.

That is, <em>P</em> (<em>X</em> > <em>s</em> + <em>x</em> | <em>X</em> ><em> s</em>) = <em>P</em> (<em>X</em> > <em>x</em>)

So the probability that a customer will spend more than 15 minutes total in the bank, given that the customer has already waited over 10 minutes  is:

P (X > 15 | X > 10) = P (X > 5)

\int\limits^{\infty}_{5} {f(x)} \, dx =\int\limits^{\infty}_{5}  {\lambda e^{-\lambda x}} \, dx\\=\int\limits^{\infty}_{5}  {0.10 e^{-0.10 x}} \, dx\\=0.10\int\limits^{\infty}_{5}  {e^{-0.10 x}} \, dx\\=0.10|\frac{e^{-0.10 x}}{-0.10}|^{\infty}_{5}\\=[-e^{-0.10 \times \infty}+e^{-0.10 \times 5}]\\=0.6065

Thus, the probability that a customer will spend more than 15 minutes total in the bank, given that the customer has already waited over 10 minutes  is 0.6065.

8 0
3 years ago
4) Determine o período e o conjunto imagem, construindo o gráfico de um período completo para cada função dada.a) por f(x) = 1+
QveST [7]

Answer:

a) 2π;  [-3,5]; b) 2π; [-2,2]

Step-by-step explanation:

(a) y = 1 + 4sin x

The general form of a sine function is  

y = A(sin(B(x - h)) + k

where

   |A| = amplitude

2π/B = T =period

     h = phase shift (horizontal shift, to the right if x > 0)

     k = vertical shift (midline is y = k)

Your function is

y = 1 + 4sin(x)  

Comparing terms, we find that

h = 0

k = 1

A = 4

B = 1

The amplitude is 4.

The midline is y = 1.

The horizontal shift is 0.

(i) Period

T = 2π/B = 2π/1 = 2π

(ii) Graph

The graph of the function is the first figure below.

(iii) Image set

The image of a function is the set of all possible values it can have.

If f(x)= 1 + 4sin(x), the domain of the function is (-∞,∞).

The corresponding values of y can take any value from -3 to 5.

The image set is [-3,5].

(b) y = 2sin(x - 3)

h = 3; k = 0; A = 2; B = 1

The amplitude is 2

The midline is y = 0.

The horizontal shift is 3 radians to the right.

(i) Period

T = 2π/B = 2π/1 = 2π

(ii) Graph

The graph of the function is the second figure below.

(iii)Image set

If f(x) = 2sin(x - 3), the domain of the function is (-∞,∞)

The corresponding values of y can take any value from -2 to 2.

The image set is [-2,2].

4 0
3 years ago
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