Answer:
True, based on the <em>Transitive Property of Equality</em>.
Step-by-step explanation:
Note that the <em>Transitive Property of Equality </em>states that "If a = b, & b = c, then a = c.
In this case it is the same.
∠1 ≅ ∠2 (because both are complementary), ∠1 ≅ ∠3 (again, both are complementary), then based on the Transitive Property, ∠2 ≅ ∠3, making all of them complementary angles
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<em>~Senpai</em>
Answer:
E. 0
Step-by-step explanation:
There isn't any guarantee that there are <em>any </em>people that have their birthdays in the same month based on what you're given, so your answer would be 0.
Answer:
48.
Step-by-step explanation:
33 + 15 = 48.
You can check your answer by subtracting 48-15, which gives you 33.
Answer:
Step-by-step explanation:
whats is the image of (12,-9 after dilation by a scale 1/3 centered at the origin?
Answer:
6.18% of the class has an exam score of A- or higher.
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean 
and standard deviation 
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:
What percentage of the class has an exam score of A- or higher (defined as at least 90)?
This is 1 subtracted by the pvalue of Z when X = 90. So
has a pvalue of 0.9382
1 - 0.9382 = 0.0618
6.18% of the class has an exam score of A- or higher.
