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dangina [55]
3 years ago
5

GIVING BRAINLIST TO ANYONE WHO SOLVES ANY QUESTION <3

Mathematics
1 answer:
brilliants [131]3 years ago
7 0

Answer:

Mild-Level 1: X=10

Medium-Level 2: X=21

Spicy Level 3: X=83

Step-by-step explanation:

You have to make sure each expression equals 90 degrees

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What do ratios compare
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In mathematics, a ratio indicates how many times one number contains another. ... When two quantities are measured with the same unit, as is often the case, their ratio is a dimensionless number. A quotient of two quantities that are measured with different units is called a rate.
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(a+b)² is equal to ?​
earnstyle [38]

Answer:

No

Step-by-step explanation:

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3 years ago
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What quantity of parsley would you need to make 5 times as much as the original recipe?
algol [13]
Original= x

5(x)=y
y= 5Xx
8 0
3 years ago
Compare factoring by grouping to factoring out the greatest common factor.
Blababa [14]

Answer:

(3x + 10)(2x + 1)

Step-by-step explanation:

Factor by grouping: 6x2 + 3x + 20x + 10.

This is a polynomial written with four terms that don't have a single common factor among them. However, the first two terms have a common factor (3x), and the last two terms have a common factor (10). This situation doesn't answer all of our wildest factoring dreams, but we'll take it.

By pulling out the common factors for each pair of terms, we can rewrite the original polynomial like this:

3x(2x + 1) + 10(2x + 1)

These two terms now have a common factor of (2x + 1). Seems like we should be able to do something with that information, don't you think? In fact, we can pull out this common factor and rewrite the polynomial again:(3x + 10)(2x + 1)

7 0
3 years ago
How much more would $8,000 earn in four years compounded daily at 5% than compounded annually at 5%?
QveST [7]

Answer:

Given the statement:

8,000 earn in four years compounded daily at 5%

To find the amount we use formula:

A = P(1+\frac{r}{n})^{nt}

where P is the principal , A is the amount , n is number of times compounded per year and t is the time in year.

Here, Principal(P) = $8000, r = 5% and n = 365

Substitute these given values we get;

A_1= 8000(1+\frac{5}{365})^{365 \cdot 4}

A_1= 8000 \cdot 1.000137^{1460}

A_1= 8000 \cdot 1.22141

Simplify:

A_1= \$9771.28

To find the Interest we use formula:

I_1= A_1-P

I_1= 9771.28 -8000 = \$1771.28

It is also given that:

8,000 earn in four years compounded annually at 5%.

Here, P = $8000, r = 5% , t =4 year and n = 1

Using the same formula to calculate the amount:

A_2 = 8000(1+\frac{5}{1})^{1 \cdot 4}

A_2= 8000(1.05)^4

Simplify:

A_2= \$9724.05

To find the Interest :

I_2= A_2 - P

I_2= 9724.05 - 8000= \$1724.05

Then;

I_1-I_2 = 1771.28-1724.05 = \$47.23

Therefore, $47.23 more would  $8,000 earn in four years compounded daily at 5% than compounded annually at 5%





6 0
4 years ago
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