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lara31 [8.8K]
2 years ago
14

A second boat passes by your port, at a distance of 1,500 feet from shore. 10 seconds later, the boat is 2,000 feet away from yo

u. how fast was the boat going?
Mathematics
1 answer:
malfutka [58]2 years ago
8 0
Speed is distance over time
So 2000-1500=500 (how far the boat went in the given time)
the time is 10 seconds
500/10=50ft/sec.
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Vera_Pavlovna [14]

Answer:

1.84

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add 2 to that and get: 2.714286

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olga_2 [115]

Answer:

1. Yes

∆RST ~ ∆WSX

by SAS

2. Yes

∆ABC ~ ∆PQR

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3. Yes

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4. Yes

∆DJK ~ ∆PZR

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5. Yes

∆JKL ~ ∆XYW

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7. Yes

∆BEF ~ ∆NML

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8. Yes

∆GHI ~ ∆QRS

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9. x=22

10. x=12

Step-by-step explanation:

1. RS/WS=ST/SX and m<RST=m<WSX

2. AB/PQ=8/6=4/3

BC/QR=AC/PR=12/9=4/3

AB/PQ=BC/QR=AC/PR

3. ST/JP=10/15=2/3

SU/JM=14/21=2/3

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4. DK/PR=8/4=2

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DK/PR=2=JK/ZR

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JL/XW=36/24=3/2

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7. BF/NL=24/16=3/2

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BF/NL=3/2=BE/NM

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8. GH/QR=32/20=8/5

HI/RS=40/25=8/5

GI/QS=24/15=8/5

GH/QR=HI/RS=GI/QS=8/5

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Simplifying the fraction on the right side of the equation:

x/33=2/3

Solving for x: Multiplying both sides of the equation by 33:

33(x/33)=33(2/3)

x=11(2)

x=22

10. x/16=9/12

Simplifying the fraction on the right side of the equation:

x/16=3/4

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