You should draw a diagram
And it should make a triangle and solve using SOH-CAH-TOA (sin cos tan) relative to your angle of 69 degrees
12km is the answer hope this heps
Answer:
Step-by-step explanation:
I think it'd be better if you gave us some sort of diagram with it?
Length of outer boundary =30m
So area of outer boundary =30×30
= 900m²
Length of inner boundary of path=30-1= 29m
Inner area =29×29 =841m²
So area of path is= outer area - inner area
=900- 841
= 59m²
