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Fiesta28 [93]
3 years ago
7

PLSS HELP ME WITH THIS!! 25 POINTS!

Mathematics
1 answer:
kap26 [50]3 years ago
5 0
X must be greater than or equal to -4, not sure how you’d plot it.
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20 POINTS WILL GIVE BRAINLIEST HELP QUICKLY!!
SVETLANKA909090 [29]

Answer:

1.function 1 has a greater rate of change than function 2

3. Function 1 has a greater y-intercept than function 2

Step-by-step explanation:

Using the table we can find the slope using

m = (y2-y1)/ (x2-x1)

m = (29-5)/ (8-0)

     = 24/8

    = 3

The rate of change for the table is 3

The y intercept is (0,5)  


Using the graph  (0,-1)  and (2,0)

m = (y2-y1)/ (x2-x1)

m = (0--1)/ (2-0)

     = (0+1)/2

    = 1/2

The y intercept is (0,-1)


Since 3>1/2 , function 1 has a greater rate of change than function 2

Since 5>-1, function 1 has a greater y-intercept than function 2

8 0
3 years ago
Read 2 more answers
Evaluate the following numerical expressions.<br> 6 + 3.4 =
avanturin [10]

Answer:

6+3.4=9.4

Step-by-step explanation:

the 6 and the 3 add normally, and you just add 0.4 in the decimal place

3 0
3 years ago
1. A basketball is slightly larger than a bowling ball. Which ball has a greater mass?
Dvinal [7]

Answer:

Bowling Ball because a bowling ball has mass in the middle. Basketballs are empty inside but Bowling Balls are more dense

Step-by-step explanation:

8 0
3 years ago
Find radius of the sphere from the following volume
nordsb [41]
Can you send a picture by chance?
3 0
2 years ago
You are designing an open-top cylindrical container. The cylinder must have a volume of 81π cm3 . The bottom of the container mu
stira [4]

Answer:

Minimum dimensions are r=3cm, h=9cm

Minimum Cost=$254.47

Step-by-step explanation:

Volume of a Cylinder=πr²h

Volume of the Open Top Cylinder=81π cm³.

Therefore:

πr²h=81π

The bottom costs $3 per cm² and the side costs $1 per cm².

Total Surface Area of the open top Cylinder= πr²+2πrh

Cost, C=3πr²+2πrh

As the Volume is fixed.

πr²h=81π

r²h=81

h=81/r²

Modifying C,

C=3\pi r^{2}+2 \pi r \frac{81}{r^{2}}

C=3\pi r^{2}+ \frac{162 \pi}{r}

We differentiate C with respect to r

C'=6\pi r -\frac{162 \pi}{r^2}

At the minimum cost, C'=0.

Next we solve C'=0 for r

6\pi r -\frac{162 \pi}{r^2}=0

6πr³-162π=0

6πr³=162π

r³=27

r=3

The dimensions of the cylinder at minimum cost are therefore:

r=3 cm

h=81/9=9cm

The minimum cost of the Cylinder

C=3πr²+2πrh

=(3XπX3²)+(2XπX3X9)

=$254.47

8 0
4 years ago
Read 2 more answers
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