Answer:
10582
Step-by-step explanation:
<span>x^2 - 3x - 28 = </span><span>(x - 7)(x + 4)
answer
first one
</span><span>(x - 7)(x + 4)
</span>
hope it helps
Answer:
vertical asymptote at x=-1
horizontal asymptote at y=0
Step-by-step explanation:
To find vertical asymptote we set the denominator =0 and solve for x
x+1=0 (subtract 1 from both sides)
x=-1
So, vertical asymptote at x=-1
To find horizontal asymptote we look at the degree of both numerator and denominator
there is no variable at the numerator , so degree of numerator =0
degree of denominator =1
When the degree of numerator is less than the degree of denominator
then horizontal asymptote at y=0
Understanding the Absolute Value.
First, know what the absolute value is.
The absolute value is the value that determines how far the value is from 0.
For example, The absolute value of -5 is far from 0 5 units. Therefore the absolute value of -5 equals 5.
Basic Absolute Value Defines
| a | = a
- | a | = -a
| - a | = a
Back to the question. To evaluate those expressions, we use the defines of absolute value.
|-16| = 16
|-1| = 1
16-(1)
Then remove the brackets. 16 - 1 = 15
Therefore, the answer is 15.
<em>The</em><em> </em><em>answer</em><em> </em><em>above</em><em> </em><em>is</em><em> </em><em>when</em><em> </em><em>being</em><em> </em><em>subtracted</em><em> </em><em>and</em><em> </em><em>evaluated</em><em> </em><em>from</em><em> </em><em>both</em><em> </em><em>16</em><em>-</em><em>1</em>
<em>Evaluating</em><em> </em><em>for</em><em> </em><em>each</em><em> </em><em>expressions</em><em> </em><em>would</em><em> </em><em>be</em>
<em>|</em><em>-</em><em>16</em><em>|</em><em> </em><em>=</em><em> </em><em>16</em>
<em>-</em><em>|</em><em>-</em><em>1</em><em>|</em><em> </em><em>=</em><em> </em><em>-</em><em>1</em>
ANSWER
M=(−3,72)
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