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Shkiper50 [21]
3 years ago
5

Two communication companies offer calling plans. With company x, it cost 35 cents to connect and then 5 cents for each minute.Wi

th company y, it cost 15 cents to connect and the 4 cents for each minute. Write and simplify an expression that represents how much more company x charges than company y, in cent, for n minutes
Mathematics
1 answer:
seropon [69]3 years ago
3 0

Answer:

34

Step-by-step explanation:

Subtract and divide

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Find the sum of an arithmetic<br> 9 terms; 2, 5, 8, 11....<br> 9
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6

Step-by-step explanation:

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Hi, I am very stuck on questions 17 and 18. Can someone help please? Thanks
NISA [10]

9514 1404 393

Answer:

  17) x = 10√2

  18) x = 4√6

Step-by-step explanation:

These problems rely on your knowledge of the side ratios of special triangles

  45°-45°-90° triangle: 1 : 1 : √2

  30°-60°-90° triangle: 1 : √3 : 2

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17) 5 is the short side of the isosceles right triangle, so its hypotenuse is 5√2. That length is the shortest side of the 30/60/90 triangle, so its longest side is 2 times that:

  x = 10√2

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18) 8 is the longest side of the 30/60/90 triangle, so its long leg will be 8(√3)/2 = 4√3. The hypotenuse of the isosceles right triangle is √2 times that, so ...

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6 0
3 years ago
1.Point E is the midpoint. Find EF. *
Soloha48 [4]

Step-by-step explanation:

Since, Point E is the midpoint of DF

Therefore,

DE = EF

10x = 4x + 12

10x - 4x = 12

6x = 12

x = 12/6

x = 2

EF = 4x + 12 = 4*2+12 = 8 * 12 = 20

EF = 20

AB = BC

6x + 2 = 9x - 10

10 + 2 = 9x - 6x

12 = 3x

12/3 = x

x = 4

BC = 9x - 10 = 9*4 - 10 = 36 - 10 = 26

5 0
3 years ago
The attention span of children (ages 3 to 5) is claimed to be Normally distributed with a mean of 15 minutes and a standard devi
Agata [3.3K]

Answer:

If the observed sample mean is greater than 17.07 minutes, then we would reject the null hypothesis.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 15 minutes

Sample size, n = 10

Alpha, α = 0.05

Population standard deviation, σ = 4 minutes

First, we design the null and the alternate hypothesis

H_{0}: \mu = 15\text{ minutes}\\H_A: \mu > 15\text{ minutes}

Since the population standard deviation is given, we use one-tailed z test to perform this hypothesis.

Formula:

z_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }

Now, z_{critical} \text{ at 0.05 level of significance for one tail} = 1.64

Thus, we would reject the null hypothesis if the z-statistic is greater than this critical value.

Thus, we can write:

z_{stat} = \displaystyle\frac{\bar{x} - 15}{\frac{4}{\sqrt{10}} } > 1.64\\\\\bar{x} - 15>1.64\times \frac{4}{\sqrt{10}}\\\bar{x} - 15>2.07\\\bar{x} > 15+2.07\\\bar{x} > 17.07

Thus, the decision rule would be if the observed sample mean is greater than 17.07 minutes, then we would reject the null hypothesis.

6 0
4 years ago
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