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anygoal [31]
2 years ago
7

Buyers are skeptical of a motorcycle advertisement that claims the newest model gets an average of 52 miles per gallon. They bel

ieve the dealer is overstating the average. Which null and alternative hypotheses should the buyers test? Let u represent the true average gas mileage.
Mathematics
1 answer:
Lana71 [14]2 years ago
3 0

Answer:

Null hypothesis; H0: µ ≥ 52 mpg

Alternative hypothesis; Ha: µ < 52 mpg

Step-by-step explanation:

We are told that the newest model gets an average of 52 miles per gallon and that the buyers believe that the average mpg was overstated.

This means the alternative hypothesis will have an average less than 52. Thus;

Null hypothesis; H0: µ ≥ 52 mpg

Alternative hypothesis; Ha: µ < 52 mpg

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Find g(x), where g(x) is the reflection across the y-axis of f(x)= –9|x–10|+1.
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Answer:

To reflect a graph, f(x) over the x-axis, you take -f(x).

So if f(x)=x^2, then -f(x) is -x^2.

Then g(x)=-x^2 is the reflection of your function f(x) over the x-axis.

Step-by-step explanation:

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3 years ago
A dime is 1/2 inch wide if you put 5 dimes end to end, how long will they be begginning to end
Contact [7]
If you put 5 which means its 2 1/2 ( I think) Because two 1/2 makes one.
8 0
3 years ago
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There are 2.54cm in an inch, 12 inches in a foot, and 5,280 feet in a mile.which expression gives the number of centimeters in a
geniusboy [140]

Answer:

(2.54×12) ×5280

Step-by-step explanation:

Since there are 2.54cm in an inch, multiply 2.54 by 12 to find out how many cm there are in a foot. Then you multiply that by 5280

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3 years ago
5m - 3n = 19; m - 6n = -7 /pls. help me solve this linear equation with two variables.
Allisa [31]

Answer:

m = 5, n = 2

Step-by-step explanation:

5m - 3 n = 19\\m - 6n = - 7 \ => m = -7 + 6n\\\\Substitute \ m  \ in \  5m - 3n = 19\\\\5(-7 + 6n) - 3n = 19\\-35 + 30n -3n = 19\\27n = 19 + 35 \\27n = 54 \\n = 2\\\\Substitute \ n = 2 \  in \  m = -7 + 6n\\\\m = -7 + (6 \times 2) = -7 + 12 = 5

5 0
3 years ago
The hypotenuse of a right triangle has endpoints A(4, 1) and B(–1, –2). On a coordinate plane, line A B has points (4, 1) and (n
GarryVolchara [31]

Answer:

(-1,1),(4,-2)

Step-by-step explanation:

Given: The hypotenuse of a right triangle has endpoints A(4, 1) and B(–1, –2).

To find: coordinates of vertex of the right angle

Solution:

Let C be point (x,y)

Distance between points (x_1,y_1),(x_2,y_2) is given by \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

AC=\sqrt{(x-4)^2+(y-1)^2}\\BC=\sqrt{(x+1)^2+(y+2)^2}\\AB=\sqrt{(4+1)^2+(1+2)^2}=\sqrt{25+9}=\sqrt{34}

ΔABC is a right angled triangle, suing Pythagoras theorem (square of hypotenuse is equal to sum of squares of base and perpendicular)

34=\left [ (x-4)^2+(y-1)^2 \right ]+\left [ (x+1)^2+(y+2)^2 \right ]

Put (x,y)=(-1,1)

34=\left [ (-1-4)^2+(1-1)^2 \right ]+\left [ (-1+1)^2+(1+2)^2 \right ]\\34=25+9\\34=34

which is true. So, (-1,1) can be a vertex

Put (x,y)=(4,-2)

34=\left [ (4-4)^2+(-2-1)^2 \right ]+\left [ (4+1)^2+(-2+2)^2 \right ]\\34=9+25\\34=34

which is true. So, (4,-2) can be a vertex

Put (x,y)=(1,1)

34=\left [ (1-4)^2+(1-1)^2 \right ]+\left [ (1+1)^2+(1+2)^2 \right ]\\34=9+4+9\\34=22

which is not true. So, (1,1) cannot be a vertex

Put (x,y)=(2,-2)

34=\left [ (2-4)^2+(-2-1)^2 \right ]+\left [ (2+1)^2+(-2+2)^2 \right ]\\34=4+9+9\\34=22

which is not true. So, (2,-2) cannot be a vertex

Put (x,y)=(4,-1)

34=\left [ (4-4)^2+(-1-1)^2 \right ]+\left [ (4+1)^2+(-1+2)^2 \right ]\\34=4+25+1\\34=30

which is not true. So, (4,-1) cannot be a vertex

Put (x,y)=(-1,4)

34=\left [ (-1-4)^2+(4-1)^2 \right ]+\left [ (-1+1)^2+(4+2)^2 \right ]\\34=25+9+36\\34=70

which is not true. So, (-1,4) cannot be a vertex

So, possible points for the vertex are (-1,1),(4,-2)

7 0
3 years ago
Read 2 more answers
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