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3 years ago

A T-shirt launcher can launch 105 shirts in 20 minutes. What is the rate in shirts per hour?

Mathematics

2 answers:

Margarita [4]3 years ago

4 0

The T-shirt launcher can launch 315 shirts per hour.

olasank [31]3 years ago

4 0

Answer:

315 shirts launched per hour

Step-by-step explanation:

you multiply 105 by 3 because theres 60 minutes in a hour

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You are given the parametric equations x=2cos(θ),y=sin(2θ). (a) List all of the points (x,y) where the tangent line is horizonta

vladimir1956 [14]

Answer:

The solutions listed from the smallest to the greatest are:

x: $-\sqrt{2}$ $-\sqrt{2}$ $\sqrt{2}$ $\sqrt{2}$

y: -1 1 -1 1

Step-by-step explanation:

The slope of the tangent line at a point of the curve is:

$m = \frac{\frac{dy}{dt} }{\frac{dx}{dt} }$

$m = -\frac{\cos 2\theta}{\sin \theta}$

The tangent line is horizontal when $m = 0$ . Then:

$\cos 2\theta = 0$

$2\theta = \cos^{-1}0$

$\theta = \frac{1}{2}\cdot \cos^{-1} 0$

$\theta = \frac{1}{2}\cdot \left(\frac{\pi}{2}+i\cdot \pi \right)$ , for all $i \in \mathbb{N}_{O}$

$\theta = \frac{\pi}{4} + i\cdot \frac{\pi}{2}$ , for all $i \in \mathbb{N}_{O}$

The first four solutions are:

x: $\sqrt{2}$ $-\sqrt{2}$ $-\sqrt{2}$ $\sqrt{2}$

y: 1 -1 1 -1

The solutions listed from the smallest to the greatest are:

x: $-\sqrt{2}$ $-\sqrt{2}$ $\sqrt{2}$ $\sqrt{2}$

y: -1 1 -1 1

6 0

3 years ago

12. If n(A) = 14, n(B) = 15, and n(<br>AB) = 6, then n(AUB) is<br>

motikmotik

Answer:

given n(A) = 14

n(B) = 15

n(A∩B ) = 15

Step-by-step explanation:

now we know that ,n(AUB) = n(A)+n(B)-n(A∩B)

n(AUB) = 14+15-6 = 23.Answer

3 0

3 years ago

Read 2 more answers

Answer questions 15 and 17 show work pls

fredd [130]

Answer:

#15) B. 30 mn^5

#17) B. 1/2

Step-by-step explanation:

The area of a trapezoid is given in the formula: 1/2(a + b) * h, where a is the length of the top of the trapezoid, b is the length of the bottom of the trapezoid, and h is the height of the trapezoid.

All of these measurements are given so all that you need to do is to substitute these values into the formula.

Substitute 3 for a, 9 for b, and 5 for h.

1/2(3 + 9) * 5

Solve inside the parentheses first. Add 3 and 9.

1/2(12) * 5

Multiply 12 and 1/2 together.

6 * 5

Multiply 6 and 5.

We need to figure out if the area is to the 5th or 6th power. When we added 3 and 9 together, we combined like terms so the exponent stayed to the 3rd power.

After multiplying this ^3 by the 5mn^2, the exponent becomes to the 5th power because you add exponents when multiplying.

Therefore the final answer is B. 30 mn^5.

When going down from 32 to 8 to 2, you can see that each number is being divided by 4.

32 / 4 = 8...

8 / 4 = 2...

So to find the next number in this sequence you would divide 2 by 4.

2 / 4 = 1/2

The answer is B. 1/2.

6 0

3 years ago

If you know this pls help ):

Aleksandr-060686 [28]

From the right hand side, we will need to find a way to rewriting 3x²y in terms of cube roots.
We know that 27 is 3³, so if we were to rewrite it in terms of cube roots, we will need to multiply everything by itself two more twice. (ie we can rewrite it as ∛(3x²y)³)

Hence, we can say that it's:
$\sqrt[3]{162x^{c}y^{5}} = \sqrt[3]{(3x^{2}y)^{3}} * \sqrt[3]{6y^{d}}$
$= \sqrt[3]{162x^{6}y^{3+d}}$

Hence, c = 6 and d = 2

4 0

3 years ago

An urn contains green and red balls. six balls are randomly drawn from the urn in succession, with replacement. that is, after e

ANEK [815]

0.022 might be the answer.

7 0

3 years ago