Answer:
The solutions listed from the smallest to the greatest are:
x:

y: -1 1 -1 1
Step-by-step explanation:
The slope of the tangent line at a point of the curve is:


The tangent line is horizontal when
. Then:



, for all 
, for all 
The first four solutions are:
x:

y: 1 -1 1 -1
The solutions listed from the smallest to the greatest are:
x:

y: -1 1 -1 1
Answer:
given n(A) = 14
n(B) = 15
n(A∩B ) = 15
Step-by-step explanation:
now we know that ,n(AUB) = n(A)+n(B)-n(A∩B)
n(AUB) = 14+15-6 = 23.Answer
Answer:
#15) B. 30 mn^5
#17) B. 1/2
Step-by-step explanation:
<h2>#15:</h2>
The area of a trapezoid is given in the formula: 1/2(a + b) * h, where a is the length of the top of the trapezoid, b is the length of the bottom of the trapezoid, and h is the height of the trapezoid.
All of these measurements are given so all that you need to do is to substitute these values into the formula.
Substitute 3 for a, 9 for b, and 5 for h.
Solve inside the parentheses first. Add 3 and 9.
Multiply 12 and 1/2 together.
Multiply 6 and 5.
We need to figure out if the area is to the 5th or 6th power. When we added 3 and 9 together, we combined like terms so the exponent stayed to the 3rd power.
After multiplying this ^3 by the 5mn^2, the exponent becomes to the 5th power because you add exponents when multiplying.
Therefore the final answer is B. 30 mn^5.
<h2>#17:</h2>
When going down from 32 to 8 to 2, you can see that each number is being divided by 4.
32 / 4 = 8...
8 / 4 = 2...
So to find the next number in this sequence you would divide 2 by 4.
The answer is B. 1/2.
From the right hand side, we will need to find a way to rewriting 3x²y in terms of cube roots.
We know that 27 is 3³, so if we were to rewrite it in terms of cube roots, we will need to multiply everything by itself two more twice. (ie we can rewrite it as ∛(3x²y)³)
Hence, we can say that it's:
![\sqrt[3]{162x^{c}y^{5}} = \sqrt[3]{(3x^{2}y)^{3}} * \sqrt[3]{6y^{d}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B162x%5E%7Bc%7Dy%5E%7B5%7D%7D%20%3D%20%5Csqrt%5B3%5D%7B%283x%5E%7B2%7Dy%29%5E%7B3%7D%7D%20%2A%20%5Csqrt%5B3%5D%7B6y%5E%7Bd%7D%7D)
![= \sqrt[3]{162x^{6}y^{3+d}}](https://tex.z-dn.net/?f=%3D%20%5Csqrt%5B3%5D%7B162x%5E%7B6%7Dy%5E%7B3%2Bd%7D%7D)
Hence, c = 6 and d = 2