Answer:
s = 22.5 m
Step-by-step explanation:
the equation for the speed change of a coach moving along a straight section of the road and starting braking at a speed of 20 m / s has the form v (t) = 25-5t. Using integral calculus, determine the coach's braking distance.
v (t) = 25 - 5 t
at t = 0 , v = 20 m/s
Let the distance is s.
Let at t = t, the v = 20
So,
20 = 25 - 5 t
t = 1 s
So, s = 25 x 1 - 2.5 x 1 = 22.5 m
For each, you'll use the slope formula
m = (y2-y1)/(x2-x1)
For function f, you'll use the two points (1,6) and (2,12) since x ranges from x = 1 to x = 2 for function f
The slope through these two points is
m = (y2-y1)/(x2-x1)
m = (12-6)/(2-1)
m = 6/1
m = 6
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For function g, you'll use (2,4) and (3,20)
The slope through these two points is
m = (y2-y1)/(x2-x1)
m = (20-4)/(3-2)
m = 16/1
m = 16
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For function h, you'll use (0,-6) and (2,-18). The y coordinates can be found by plugging in x = 0 and x = 2 respectively into h(x)
The slope through these two points is
m = (y2-y1)/(x2-x1)
m = (-18-(-6))/(2-0)
m = (-18+6)/(2-0)
m = (-12)/(2)
m = -6
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The order from left to right is: h, f, g
Answer:
-12x+18x²
Step-by-step explanation:
Given: 
Distributive property of multiplication under which a number is multiplied by the sum of two number, the first number can be distributed to both of those number.
∴
solving it by using distributive property
= 
= 
Opening parenthesis
= 
Hence, -12x+18
is the result after using distributive property.
Answer:
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Step-by-step explanation:
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