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3 years ago

If h(x) = x-7 and g(x)

Mathematics

1 answer:

shtirl [24]3 years ago

8 0

Answer:

If you would like to find the equivalent expression to (g*h)(5), you can do this using the following steps:

h(x) = x - 7

g(x) = x^2

(g*h)(x) = g(h(x)) = g(x - 7) = (x - 7)^2

(g*h)(5) = g(h(5)) = g(5 - 7) = (5 - 7)^2 = (-2)^2 = 4

The correct result would be (5 - 7)^2.

Step-by-step explanation:

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HELP I NEED HELP ASAP

Vaselesa [24]

Answer:

The answer is D

${x}^{2} + 6x + 9 = 0 \\ x = - 3$

That's the only equation will get us one point

3 0

3 years ago

The length of a rectangle is 5 inches more than its vedth. The area of the rectangle is equal to

jarptica [38.1K]

Answer:

The width = x = 14

The length = x+5 = 14+5 = 19

Step-by-step explanation:

Let l = length, w = width, A = area = l×w , and P = perimeter = 2(l+w)

Let 'x' be the width

As the length 'l' of a rectangle is 5 inches more than its width.

so the length will be = x+5

As the Area of the rectangle is equal to 2 inches more than 4 times the perimeter.

A = 4P + 2

so the equation becomes

l × w = 4×2(l+w)+2

substituting w=x, l = x+5,

(x+5)x = 8(x+5+x)+2

x²+5x = 8(5+2x)+2

x²+5x = 40+16x+2

x²+5x = 16x+42

x²+5x-16x-42 =0

x²-11x-42=0

$x^2-11x=42$

$\mathrm{Add\:}a^2=\left(-\frac{11}{2}\right)^2\mathrm{\:to\:both\:sides}$

$x^2-11x+\left(-\frac{11}{2}\right)^2=42+\left(-\frac{11}{2}\right)^2$

$x^2-11x+\left(-\frac{11}{2}\right)^2=\frac{289}{4}$

$\left(x-\frac{11}{2}\right)^2=\frac{289}{4}$

$\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}$

solving

$x-\frac{11}{2}=\sqrt{\frac{289}{4}}$

$x-\frac{11}{2}=\frac{\sqrt{289}}{\sqrt{4}}$

$x-\frac{11}{2}=\frac{\sqrt{289}}{2}$

$x-\frac{11}{2}=\frac{17}{2}$

$x-\frac{11}{2}+\frac{11}{2}=\frac{17}{2}+\frac{11}{2}$

$x=14$

similarly solving

$x-\frac{11}{2}=-\sqrt{\frac{289}{4}}$

$x-\frac{11}{2}=-\frac{17}{2}$

$x-\frac{11}{2}+\frac{11}{2}=-\frac{17}{2}+\frac{11}{2}$

$x=-3$

x = 14, or x = -3

As the width 'x' can not be negative.

so x = 14

Thus,

The width = x = 14

The length = x+5 = 14+5 = 19

6 0

3 years ago

What is the sum of the 1st square number and the 6th square number?

Dimas [21]

Answer:

Step-by-step explanation:

1+36=37

6 0

3 years ago

Which one is the right graph

Veronika [31]

Answer: C

Step-by-step explanation:

The formula for a volume of a square-based prism is L² x h

If we insert 2 for L

We get 2² x 12 = 48

Same thing if we insert 3

3² x 12 = 108

As L is increasing, the volume is also increasing, so options A and D are out

The growth of the volume is not linear; it's exponential, eliminating B to make C the answer

If you want something visual, you can put y=12x² into a graphing calculator.

6 0

3 years ago

Find the quadratic function that has the vertex (4,5) and passes through the point (8,21) If possible, can you explain the work?

Ganezh [65]

Start by looking at the vertex form of a quadratic function, f(x) = a(x - h)^2 + k. The variables h and k are the values of the vertex. Plug those in to get f(x) = a(x - 4)^2 + 5. To find the variable a, plug in the point given for the x and y values. So, you get (21) = a((8) - 4)^2 + 5. Solve for a algebraically, and you get a = 1. Finally, plug everything in and simplify the equation. You should get that the quadratic function is f(x) = x^2 - 8x + 21. Hope this helps!

8 0

4 years ago