Answer:
GCF OF 20 AND 32: 4
Gcf of 45 and 75: 15
Step-by-step explanation:
GcF of 20 and 32
Factors of 20: 1, 2, 4, 5, 10, 20
Factors of 32: 1, 2, 4, 8, 16, 32
COMMON FACTORS: 1, 2, 4
GCF:4
Gcf of 45 and 75
Factors of 45: 15, 9, 5, 3, 1.
Factors of 75: 25, 15, 5, 3, 1.
CommoN factors: 1, 3, 5, 15
GCF:15
HOPE OT HELPED
To solve this problem you need the function
h(t) = -16t2 + v0t + h0
where t = time
v0 is the initial velocity, which in our case is 0
h0 = initial height, which in our case is 256
h(t) = 0 since we want to know when the ball will hit the ground.
0 = -16 t2 + 256
And we can solve for t
If we rearrange the terms we see that this is a difference of 2 squares
0 = 256 - 16t2
0 = (16-4t)(16+4t)
Setting each factor = 0
16-4t=0 16+4t=4
t = 4 t = -4
The second solution is discarded as time cannot be negative.
So the ball will hit the ground in 4 seconds.
Answer: it’s 20m long
I can’t explain .—.
