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crimeas [40]
3 years ago
14

60 Points PLEASE HELP. I have no more points after this lol so help please

Mathematics
2 answers:
crimeas [40]3 years ago
6 0

Area of first ∆ :-

A = 1/2 * b * h

A = 1/2 * 14.5 cm * 6cm

A = 3 × 14.5 cm²

A = 43.5 cm²

Area of second ∆ :-

A = 1/2 * ( sum of || sides) * h

A = 1/2 * ( 9 cm + 19cm) * 8cm

A = 4cm * 28cm

A = 112 cm²

vampirchik [111]3 years ago
5 0

Answer: What should i help with? I'll be happy to help but it shows nothing. I'll tell you what you wrote=)

What you wrote: 60 Points PLEASE HELP. I have no more points after this lol so help please

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Given
Soloha48 [4]

Answer:

what? I don't get it?

Step-by-step explanation:

4 0
3 years ago
If C= (-10, -9, -8, -7 ,-6 , -5) and D= ( -6, -5, -4, -3, -2, -1, ) , what is C n D ?
andrey2020 [161]

Answer:

C ∩ D = -5, -6

Step-by-step explanation:

Commons ones in both C and D are -5 and -6

7 0
2 years ago
The sum of the square of a positive number and the square of 44 more than the number is 8080. what is the​ number?
mash [69]
Let the number be x, therefore, its square is x², and 44 more than the number is x+44 whose square is (x+4)².
Thus the sum will be x² + (x+44)²² = 8080
                                  x² + x² + 88x + 1936= 8080 Combining the right terms 
                                  2x² + 8x - 6144 = 0 dividing by 2
                                     x² + 44x - 3072 =0 solving for x
                          x = 37.6 or -81.6
Therefore, the positive number is 37.6
                                
5 0
3 years ago
Read 2 more answers
What is the quotient in simplified form? State any restrictions on the variable? \frac{x^2-16}{x^2+5x+6} /\frac{x^2+5x+4}{x^2-2x
lora16 [44]
\frac{x^2-16}{x^2+5x+6} / \frac{x^2+5x+4}{x^2-2x-8}

We can begin by rearranging this into multiplication:

\frac{x^2-16}{x^2+5x+6} * \frac{x^2-2x-8}{x^2+5x+4}

Now we can factor the numerators and denominators:

\frac{(x+4)(x-4)}{(x+3)(x+2)} * \frac{(x-4)(x+2)}{(x+4)(x+1)}

The factors (x+4) and (x+2) cancel out, leaving us with:

\frac{(x-4)}{(x+3)} * \frac{(x-4)}{(x+1)}

Our answer comes out to be:

\frac{(x-4)^{2} }{(x+3)(x+1)} or \frac{ x^{2} -8x+16}{ x^{2}+4x+3 }

Based on the numerator of the second fraction (since we used its inverse), the denominators of both, and the factors we canceled out earlier, the restrictions are x ≠ -4, -3, -2, -1, 4
4 0
3 years ago
I need help with #13
Marizza181 [45]
40 ft of 60% (.6) = 24ft

Area- 24(40)=960ft
5 0
3 years ago
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