Using the Pythagorean theorem, the other leg measures:
x = sqrt(35^2 - 32.6^2) = 12.74 cm
Since this is a right triangle, the base and height are simply the two sides that are perpendicular to each other.
Then the approximate area is (1/2)(leg 1)(leg 2) = (1/2)(32.6)(12.74) = 207.6 cm^2.
Answer:
Step-by-step explanation:
<em>Rule need to remember to solve such questions</em><em>:</em>
Answer:
82.97cm^2
Step-by-step explanation:
Given data
Circumference= 131.88 centimeters
We want to find the area of 6/10 part of a circle
Firstly, let us find the area of the circle
We need to get the radius
C= 2πr
131.88= 2*3.142*r
131.88=6.284r
r= 131.88/6.284
r=20.98 cm
Area= πr^2
Area= 3.142*20.98^2
Area= 3.142*440.16
Area= 1382.98cm^2
Hence 6/10 of a 1382.98
=0.06*1382.98
=82.97cm^2
The tangent ratio is used for right triangles
X=-2y+3
Is your answer hope this helps
