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blsea [12.9K]
3 years ago
9

1. Which set of ordered pairs is NOT a function?

Mathematics
1 answer:
puteri [66]3 years ago
3 0

Answer:

I think it's a

Step-by-step explanation:

a - many-to-many

b - many-to-one

c - one-to-one

d - one-to-one

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show that thw roots of the equation (x-a)(x_b)=k^2 are always real if a,b and k are real. Please I really need help with this
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see explanation

Step-by-step explanation:

Check the value of the discriminant

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