Answer:
The top is 5
The right side is 5
The bottom is 2x = 2*5 = 10
The left is 5-2 = 3
Step-by-step explanation:
The perimeter is the sum of the sides
x+x+ 2x + x-2 = 23
Combine like terms
5x-2 = 23
Add 2 to each side
5x-2+2 = 23+2
5x = 25
Divide each side
5x/5 = 25/5
x = 5
The top is 5
The right side is 5
The bottom is 2x = 2*5 = 10
The left is 5-2 = 3
2 2/5=12:5
5 1/5= 26:5
12:26:5
I think.
Summaation of a sequence
or see a smaller scale
from 1 to 10
notice
1+10=11
2+9=11
etc
5+6=11
10/2=5
there are 5 pairs
5*11=55
so
1 to 100
1+100=101
2+99=101
...
50+51=101
100/2=50
there ar 50 pairs
50 times 101=5050
the sum is 5050
Answer:
5.04
Step-by-step explanation:
Dale drove to the mountains last weekend. there was heavy traffic on the way there, and the trip took 7 hours. when dale drove home, there was no traffic and the trip only took 5 hours. if his average rate was 18 miles per hour faster on the trip home, how far away does dale live from the mountains? do not do any rounding.
Answer:
Dale live 315 miles from the mountains
Step-by-step explanation:
Let y be the speed of Dale to the mountains
Time taken by Dale to the mountains=7 hrs
Therefore distance covered by dale to the mountain = speed × time = 7y ......eqn 1
Time taken by Dale back home = 5hours
Since it speed increased by 18 miles per hour back home it speed = y+18
So distance traveled home =speed × time = (y+18)5 ...... eqn 2
Since distance cover is same in both the eqn 1 and eqn 2.
Eqn 1 = eqn 2
7y = (y+18)5
7y = 5y + 90
7y - 5y = 90 (collection like terms)
2y = 90
Y = 45
Substitute for y in eqn 1 to get distance away from mountain
= 7y eqn 1
= 7×45
= 315 miles.
∴ Dale leave 315 miles from the mountains
