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solmaris [256]
3 years ago
7

Graph f(x)=−1.5x+6. Use the line tool and select two points to graph the line.

Mathematics
1 answer:
aev [14]3 years ago
7 0

Answer: Points (-1 , 7.5), (0 , 6), and (1 , 4.5).

Step-by-step explanation:

You might be interested in
Find the length of each side of the polygon for the given perimeter.<br> P = 48
Vaselesa [24]

Answer:

The top is 5

The right side is 5

The bottom is 2x = 2*5 = 10

The left is 5-2 = 3

Step-by-step explanation:

The perimeter is the sum of the sides

x+x+ 2x + x-2 = 23

Combine like terms

5x-2 = 23

Add 2 to each side

5x-2+2 = 23+2

5x = 25

Divide each side

5x/5 = 25/5

x = 5

The top is 5

The right side is 5

The bottom is 2x = 2*5 = 10

The left is 5-2 = 3

6 0
3 years ago
Write the ratio:2 2/5to 5 1/5 as a fraction in the lowest terms
yuradex [85]
2 2/5=12:5
5 1/5= 26:5
12:26:5
I think.
4 0
3 years ago
Add the numbers from 1 to 100 by following the same steps you used in 1.
oksano4ka [1.4K]
Summaation of a sequence

or see a smaller scale
from 1 to 10
notice
1+10=11
2+9=11
etc
5+6=11
10/2=5
there are 5 pairs
5*11=55

so

1 to 100
1+100=101
2+99=101
...
50+51=101

100/2=50
there ar 50 pairs
50 times 101=5050

the sum is 5050
3 0
3 years ago
4.) 14% of 36 is what?
Gala2k [10]

Answer:

5.04

Step-by-step explanation:

8 0
3 years ago
Dale drove to the mountains last weekend. There was heavy traffic on the way there, and the trip took hours. When Dale drove hom
IrinaK [193]

Dale drove to the mountains last weekend. there was heavy traffic on the way there, and the trip took 7 hours. when dale drove home, there was no traffic and the trip only took 5 hours. if his average rate was 18 miles per hour faster on the trip home, how far away does dale live from the mountains? do not do any rounding.

Answer:

Dale live 315 miles from the mountains

Step-by-step explanation:

Let y be the speed  of Dale to the mountains

Time taken by Dale to the mountains=7 hrs

Therefore distance covered by dale to the mountain = speed × time = 7y ......eqn 1

Time taken by Dale back home = 5hours

Since it speed increased by 18 miles per hour back home it speed = y+18

So distance traveled home =speed × time = (y+18)5 ...... eqn 2

Since distance cover is same in both the eqn 1 and eqn 2.

Eqn 1 = eqn 2

7y = (y+18)5

7y = 5y + 90

7y - 5y = 90 (collection like terms)

2y = 90

Y = 45

Substitute for y in eqn 1 to get distance away from mountain

= 7y eqn 1

= 7×45

= 315 miles.

∴ Dale leave 315 miles from the mountains

4 0
3 years ago
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