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bazaltina [42]
3 years ago
7

Find the sum of: 72 − 104 + 5 and -32 + 4 - 10. What should be added to 32 + 32 + 3 to get 3 + 3 ? (1 mark) 3. Subtract the sum

of 12ab –10bc –18ac and 9ab + 12bc + 14ac from the sum of ab + 2bc and 3bc – ac. Answer these with Explanation To be marked as BRAINLIEST!
Mathematics
1 answer:
Rzqust [24]3 years ago
5 0

Answer:

a). -65

b). -61

c). -20ab + 3bc +3ac

Step-by-step explanation:

According To the Question,

a). the sum of 72 − 104 + 5 and -32 + 4 - 10 .

  • (72 − 104 + 5) + (-32 + 4 - 10)
  • (-27) + (-38)
  • -27 - 38
  • -65

b). What should be added to 32 + 32 + 3 to get 3 + 3 , Let X be Added .

  • Thus,  (32 + 32 + 3) + X = 3 + 3
  • 67 + X = 6
  • X = 6 - 67
  • X = -61

c). Subtract  the sum of 12ab –10bc –18ac and 9ab + 12bc + 14ac from the sum of ab + 2bc and 3bc – ac.

  • Thus, [(ab + 2bc) + (3bc – ac)] - [( 12ab –10bc –18ac) + (9ab + 12bc + 14ac)]
  • (ab + 5bc - ac) - (21ab + 2bc - 4ac)
  • ab + 5bc - ac - 21ab - 2bc + 4ac
  • -20ab + 3bc + 3ac

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Step-by-step explanation:

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3 years ago
A new teen magazine has a readership goal of 3.5 million. It's current readership is 2.8 million. How much does its readership n
Kazeer [188]

3,500,000 - 2,800,000 = 700,000

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3 years ago
Read 2 more answers
There are 10 pencils in a desk. Ninety percent of the pencils are sharpened. Which equation can be used to find the number of sh
dezoksy [38]
Mc012-2.jpg ........................ 10/90%= 11.1111111111111 
5 0
4 years ago
Memory module consists of 9 chips. The device is designed with redundancy so that it works even if one of its chips is defective
soldier1979 [14.2K]

Answer:

a) P[C]=p^n

b) P[M]=p^{8n}(9-8p^n)

c) n=62

d) n=138

Step-by-step explanation:

Note: "Each chip contains n transistors"

a) A chip needs all n transistor working to function correctly. If p is the probability that a transistor is working ok, then:

P[C]=p^n

b) The memory module works with when even one of the chips is defective. It means it works either if 8 chips or 9 chips are ok. The probability of the chips failing is independent of each other.

We can calculate this as a binomial distribution problem, with n=9 and k≥8:

P[M]=P[C_9]+P[C_8]\\\\P[M]=\binom{9}{9}P[C]^9(1-P[C])^0+\binom{9}{8}P[C]^8(1-P[C])^1\\\\P[M]=P[C]^9+9P[C]^8(1-P[C])\\\\P[M]=p^{9n}+9p^{8n}(1-p^n)\\\\P[M]=p^{8n}(p^{n}+9(1-p^n))\\\\P[M]=p^{8n}(9-8p^n)

c)

P[M]=(0.999)^{8n}(9-8(0.999)^n)=0.9

This equation was solved graphically and the result is that the maximum number of chips to have a reliability of the memory module equal or bigger than 0.9 is 62 transistors per chip. See picture attached.

d) If the memoty module tolerates 2 defective chips:

P[M]=P[C_9]+P[C_8]+P[C_7]\\\\P[M]=\binom{9}{9}P[C]^9(1-P[C])^0+\binom{9}{8}P[C]^8(1-P[C])^1+\binom{9}{7}P[C]^7(1-P[C])^2\\\\P[M]=P[C]^9+9P[C]^8(1-P[C])+36P[C]^7(1-P[C])^2\\\\P[M]=p^{9n}+9p^{8n}(1-p^n)+36p^{7n}(1-p^n)^2

We again calculate numerically and graphically and determine that the maximum number of transistor per chip in this conditions is n=138. See graph attached.

6 0
4 years ago
How do you solve this 5b-28>27
damaskus [11]
B>11 hope this helps :)

8 0
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