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3 years ago

Solve for x "9x^2-x=0"

Mathematics

1 answer:

Anestetic [448]3 years ago

4 0

$9x^2-x=0\\
x(9x-1)=0\\
x=0 \vee x=\dfrac{1}{9}$

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Answer:

Step-by-step explanation:

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3 years ago

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3 years ago

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Step-by-step explanation:

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3 years ago

A random variable x follows a normal distribution with mean d and standard deviation o=2. It is known that x is less than 5 abou

Vaselesa [24]

Answer:

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Step-by-step explanation:

Here's how to solve this problem using a normal distribution table.

Let $z$ be the

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In this question, $x = 5$ and $\sigma = 2$ . The equation becomes

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To solve for $\mu$ , the mean of this distribution, the only thing that needs to be found is the value of $z$ . Since

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The problem is that the normal distribution tables list only the value of $P(0 \le Z \le z)$ for $z \ge 0$ . To estimate $z$ from $P(Z \le z) = 0.6985$ , it would be necessary to find the appropriate

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