3 years ago

Solve for x "9x^2-x=0"

Mathematics

1 answer:

Anestetic [448]3 years ago

4 0

$9x^2-x=0\\
x(9x-1)=0\\
x=0 \vee x=\dfrac{1}{9}$

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gogolik [260]

Answer:

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Step-by-step explanation:

Given parameters:

Amount of interest earned = $40

Principal = $400

Interest rate = 5%

Unknown:

Time taken for the money to be in bank = ?

Solution:

The formula for interest is given as:

I = $\frac{PRT}{100}$

Where I is the interest

P is the principal

R is the rate

T is the time

So;

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photoshop1234 [79]

$\text{Given that }\$7000 \text{ is compounded semiannualy at a rate of }11\% \text{ for 21 years}\\
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\text{we know that the amount after t year when compounded is given by}\\
\\
A=P\left ( 1+\frac{r}{n} \right )^{nt}\\
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\text{here P is the principal amoount, so }P=7000,\\
\\
\text{r is the interest rate, }r=11\%=0.11\\
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\text{n is the number of times in a year, here semiannulay, so }n=2,\\
\\
\text{and t is the time, so }t=21\\
\\
\text{so the amount after 21 years is}$

$A=7000\left ( 1+\frac{0.11}{2} \right )^{2(21)}\\
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\Rightarrow A=7000\left ( 1+0.055 \right )^{42}\\
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\Rightarrow A=7000\left ( 1.055 \right )^{42}\\
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\Rightarrow A\approx 66328.68$

So the amount after 21 years is: $66328.68

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