3 years ago

Solve for x "9x^2-x=0"

1 answer:

4 0

$9x^2-x=0\\
x(9x-1)=0\\
x=0 \vee x=\dfrac{1}{9}$

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Gnoma [55]

The answer is 7.07 times, with rounding, still 7.07.

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3 years ago

dangina [55]

Answer: 3+15+9+19=46

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3 years ago

Vesna [10]

Answer:

The equivalent expression is:

$16x^4-81=(4x^2-9)(4x^2+9)$

Step-by-step explanation:

We have been given the equation:

$f(x)=16x^4-81=0$

Equivalent expression can be computed by solving the expression ai its maximum.

We can factorize the given equation:

By using $a^2-b^2=(a+b)(a-b)$

Here, $a=4x^2,b=9$

Hence, we get the equation below:

$16x^4-81=(4x^2-9)(4x^2+9)$

Therefore, the equivalent expression is:

$16x^4-81=(4x^2-9)(4x^2+9)$

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3 years ago

Juli2301 [7.4K]

Aida did not correctly divide by the common factor to get (4+8).

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3 years ago

aliina [53]

it will have to be 5/9 or0.5555555556

8 0

3 years ago