3 years ago

In the triangle below, with right angle ZE, suppose that m ZD= (3x+38) and mZF=(4x+3)°.

1 answer:

5 0

Answer:

$for \: a \: right \: angled \: triangle \\ (3x + 38) + (4x + 3) + 90 = 180 \\ (4 + 3)x = 180 - (90 + 38 + 3) \\ 7x = 49 \\ x = 7 \\ \\ mZD=(3x + 38) \\ = (3 \times 7) + 38\\ mZD = 59° \\ \\ mZF=(4x+3)° \\ = (4 \times 7) + 3 \\ mZF = 31°$

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