Try out this website or search "surface area of a triangular prism" in Google
http://www.ck12.org/geometry/Surface-Area-of-Triangular-Prisms/lesson/Surface-Area-of-Triangular-Pri...
Hi there!
We are given:
cos(7x)cos(4x) = -1 - sin(7x)sin(4x)
Begin by moving all terms with variables to one side:
cos(7x)cos(4x) + sin(7x)sin(4x) = -1
The corresponding trig identity is cos(A - B). Thus:
cos(7x - 4x) = cos(7x)cos(4x) + sin(7x)sin(4x) = -1
cos(3x) = -1
cos = -1 at π, so:
3x = π
x = π/3
We can also find another solution. Let 3π = -1:
3x = 3π
x = π
Thus, solutions on [0, 2π) are π/3 and π.
Answer:
s
Step-by-step explanation:
Answer:I don't know if you're asking for equation or not cause you didn't mention the question so I'm just gonna write down the equation.
y=4.2x+3.4
Use this formula➡️y=mx+b
m is slope, b is y-intercept , x and y are the points like (0, 3.4)
You said it's the y-intercept but it's not. it's just a point on the graph
Step-by-step explanation:
The answer would be theorem Side angle side (aka SAS)
