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leonid [27]
2 years ago
9

20 PTS!!!! HELP!!!!! Look at picture​

Mathematics
2 answers:
Sav [38]2 years ago
7 0

Answer:

b only

Step-by-step explanation:

chubhunter [2.5K]2 years ago
3 0
The answer is in quadrant 1
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50 out of 100 flowers are red. What percentage of the flowers are red
GuDViN [60]

Answer:

50%

Step-by-step explanation:

duhh, sorry this one just very obvious

7 0
3 years ago
On a coordinate plane, 2 exponential fuctions are shown. Function f (x) decreases from quadrant 2 into quadrant 1 and approaches
Gala2k [10]

Answer:

g(x)=6(3)^x

Step-by-step explanation:

We are given  that

f(x)=6(\frac{1}{3})^x

Function f decreases from quadrant  2 to quadrant 1 and approaches  y=0

It cut the y- axis at (0,6) and passing through the point (1,2).

Function g(x) approaches y=0 in quadrant 2 and increases into quadrant 1.

It passing through the point (-1,2) and cut the y-axis at point (0,6).

Reflection across y- axis:

Rule of transformation is given by

(x,y)\rightarrow (-x,y)

Using the rule then we get

g(x)=6(\frac{1}{3})^{-x}=6(3)^x

By using

x^{-a}=\frac{1}{x^a}

Substitute x=-1

g(-1)=6\times (\frac{1}{3})=2

Substitute x=0

g(0)=6

Therefore,g(x)=6(3)^x is true.

8 0
3 years ago
Read 2 more answers
Alpha printing will make 400 brochures for $100. Omega printing will make 1,000 brochures for $100. How much money will you save
Dmitriy789 [7]

it is given in the question that

Alpha printing will make 400 brochures for $100. Omega printing will make 1,000 brochures for $100.

For Alpha, cost of 1 brochure is

= \frac{100}{400} = $0.25

For Omega,

Cost of 1 brochure is

= \frac{100}{1000} = 0.10

So choosing Omega printing, you will save

= 0.25-0.10 = $0.15

on each brochure .

6 0
3 years ago
A converging lens of focal length 5 cm is placed at a distance of 20
lesya [120]

The object should be placed 20/cm from the lens so as to form its real image on the screen

<h3>Mirror equation</h3>

The mirror equation is given according to the expression below;

1/f = 1/u + 1/v

where

f is the focal length

u is the object distance

v is the image distance

Given the following parameters

f = 5cm

v = 20cm

Required

object distance u

Substitute

1/5 = 1/u +1/20

1/u = 1/5-1/20
1/u = 3/20

u = 20/3 cm

Hence the object should be placed 20/cm from the lens so as to form its real image on the screen

Learn more on mirror equation here; brainly.com/question/27924393

#SPJ1

4 0
2 years ago
Help please !! Anything would be greatly appreciated thank you
kirill115 [55]

Boleh translate in Malay?

6 0
3 years ago
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