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MaRussiya [10]
4 years ago
15

Which assumption will work best for a large data set with a normal distribution? a.Most of the data points are close to the mini

mum value of the set. b. Most of the data points are close to the maximum value of the set. c. Most of the data points are close to the mean value of the set d. The data points are distributed uniformly over the range of the set.
Mathematics
2 answers:
masha68 [24]4 years ago
3 0
I think the correct answer would be option C. The best assumption that will work for a large data set having a normal distribution would be that most of the data points are close to the mean value of the set. Having this assumption, we can use freely the common measures of central tendency as statistical tools.
11Alexandr11 [23.1K]4 years ago
3 0

Answer:

Option C) Most of the data points are close to the mean value of the set

Step-by-step explanation:

We are given the following information in the question:

Properties of Normal Distribution

  • It is a probability distribution which  is symmetric about the mean that means data near the mean.
  • In graph form, normal distribution will appear as a bell curve.
  • In a normal distribution, Mean = Mode = Median

We have to choose the best assumption that will work for a large data set with normal distribution.

Option C) Most of the data points are close to the mean value of the set

It is one of the properties of the normal distribution. Most of the data point cannot be close to the minimum or maximum value and nor the data can be distributed uniformly over the range of the set.

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Answer:

There are (63) combinations. The notation means "six choose three". Out of six items (flavors) choose three.

(nk)=n!k!(n−k)!.

(63)=6!3!3!.

Think of it this way. There are 6 ways to choose a flavor. Once you choose, there are 5 ways to choose the next. After that, there are 4 flavors left. which is 6!/3!=6⋅5⋅4⋅3⋅2⋅13⋅2⋅1=6⋅5⋅4=120.

But, you could have chosen {chocolate,vanilla,strawberry} and you get the same combination as {vanilla, strawberry, chocolate} so we have to divide by 3!=3⋅2⋅1=6 to account for the order of choosing.

So the number of combinations of flavors is (63)=1206=20.

<h3>Mark me a brainlist</h3>

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