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WINSTONCH [101]
3 years ago
5

Please help, I’ll give brainlyist FIND THE MEASURE OF A

Mathematics
1 answer:
Ksenya-84 [330]3 years ago
6 0

Answer:

18°

Step-by-step explanation:

The m∠A ≅ x+32

The angle opposite 36° is 36° & the angle opposite x+126 is x + 126: Vertical angles theorem

The three angles in the triangle with m∠A are 36°, x+126°, and x+32°(m∠A)

36+x+126+x+32 = 180 : Angles in a triangle theorem

194+2x = 180

2x = -14

x= -7

m∠A ≅ -14+32

m∠A≅ 18°

I hope this helps!!!

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Could anyone prove this question correct... pls... I will mark branliest for step by step solution.
Masja [62]

Answer:

C

Step-by-step explanation:

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3 years ago
What is the surface area of the cylinder in terms of ? The diagram is not drawn to scale.
Delicious77 [7]

Answer:

SA = 748π in²

General Formulas and Concepts:

<u>Symbols</u>

  • π (pi) ≈ 3.14

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Geometry</u>

Surface Area of a Cylinder Formula: SA = 2πrh + 2πr²

  • <em>r</em> is radius
  • <em>h</em> is height

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify variables</em>

<em>r</em> = 11 in

<em>h</em> = 23 in

<u>Step 2: Find Surface Area</u>

  1. Substitute in variables [Surface Area of a Cylinder Formula]:                       SA = 2π(11 in)(23 in) + 2π(11 in)²
  2. Evaluate exponents:                                                                                         SA = 2π(11 in)(23 in) + 2π(121 in²)
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2 years ago
What is 75% of 180?​
OverLord2011 [107]

Hello There!

75% of 180 is 135.

Converting Percent To Decimal.

p = 75%/100 = 0.75

Y = 0.75 * 180

Y = 135

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3 years ago
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Solve the system by elimination.(show your work)
PilotLPTM [1.2K]

Answer:

x = 1 , y = 1 , z = 0

Step-by-step explanation by elimination:

Solve the following system:

{-2 x + 2 y + 3 z = 0 | (equation 1)

-2 x - y + z = -3 | (equation 2)

2 x + 3 y + 3 z = 5 | (equation 3)

Subtract equation 1 from equation 2:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x - 3 y - 2 z = -3 | (equation 2)

2 x + 3 y + 3 z = 5 | (equation 3)

Multiply equation 2 by -1:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+3 y + 2 z = 3 | (equation 2)

2 x + 3 y + 3 z = 5 | (equation 3)

Add equation 1 to equation 3:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+3 y + 2 z = 3 | (equation 2)

0 x+5 y + 6 z = 5 | (equation 3)

Swap equation 2 with equation 3:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y + 6 z = 5 | (equation 2)

0 x+3 y + 2 z = 3 | (equation 3)

Subtract 3/5 × (equation 2) from equation 3:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y + 6 z = 5 | (equation 2)

0 x+0 y - (8 z)/5 = 0 | (equation 3)

Multiply equation 3 by 5/8:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y + 6 z = 5 | (equation 2)

0 x+0 y - z = 0 | (equation 3)

Multiply equation 3 by -1:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y + 6 z = 5 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Subtract 6 × (equation 3) from equation 2:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y+0 z = 5 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Divide equation 2 by 5:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+y+0 z = 1 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Subtract 2 × (equation 2) from equation 1:

{-(2 x) + 0 y+3 z = -2 | (equation 1)

0 x+y+0 z = 1 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Subtract 3 × (equation 3) from equation 1:

{-(2 x)+0 y+0 z = -2 | (equation 1)

0 x+y+0 z = 1 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Divide equation 1 by -2:

{x+0 y+0 z = 1 | (equation 1)

0 x+y+0 z = 1 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Collect results:

Answer: {x = 1 , y = 1 , z = 0

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