Answer:
a. 28
Step-by-step explanation:
Given:
![155.78=2.95h+73.18](https://tex.z-dn.net/?f=155.78%3D2.95h%2B73.18)
We need to evaluate given expression to find the value of 'h'.
Solution:
![155.78=2.95h+73.18](https://tex.z-dn.net/?f=155.78%3D2.95h%2B73.18)
Now first we will apply Subtraction property of equality and subtract both side by 73.18 we get;
![155.78-73.18=2.95h+73.18-73.18\\\\82.6=2.95h](https://tex.z-dn.net/?f=155.78-73.18%3D2.95h%2B73.18-73.18%5C%5C%5C%5C82.6%3D2.95h)
Now we will use Division property of equality and divide both side by 2.95 we get;
![\frac{82.6}{2.95}=\frac{2.95h}{2.95}\\\\h=28](https://tex.z-dn.net/?f=%5Cfrac%7B82.6%7D%7B2.95%7D%3D%5Cfrac%7B2.95h%7D%7B2.95%7D%5C%5C%5C%5Ch%3D28)
Hence After evaluating given expression we get the value of 'h' as 28.
Answer:
(C) 32
Step-by-step explanation:
This is a problem of Permutation and Combination, not probability.
This clarification is given because most questions like this are on Probability and Statistics.
The researcher has recruited 8 participants and must divide them into two groups of 4 people each.
So there's:
GROUP A - Placebo Group
GROUP B - Experimental Group
Since the experiment is on humans - distinct objects - they will have distinct identities. Assume the 8 participants are lined up according to identities 1,2,3,4, 5,6,7,8
[2+2+2+2 +2+2+2+2] × 2 = 16×2 = 32
Answer:
Step-by-step explanation:
look for the stem and leafs that are less than 10 and add them all up
5+7+9
Because the factors in the numerator cancel with the factors in the denominator. Consider this example:
![\dfrac{6^7}{6^4} = \dfrac{6\times6\times6\times6\times6\times6\times6}{6\times6\times6\times6} = 6\times6\times6 = 6^3 = 6^{7-4}](https://tex.z-dn.net/?f=%20%5Cdfrac%7B6%5E7%7D%7B6%5E4%7D%20%3D%20%5Cdfrac%7B6%5Ctimes6%5Ctimes6%5Ctimes6%5Ctimes6%5Ctimes6%5Ctimes6%7D%7B6%5Ctimes6%5Ctimes6%5Ctimes6%7D%20%3D%206%5Ctimes6%5Ctimes6%20%3D%206%5E3%20%3D%206%5E%7B7-4%7D%20)
All of the 6's in the denominator canceled with the 6's in the numerator, and only 3 6's "survived". The opposite can also happen, if there are more terms in the denominator:
![\dfrac{2^2}{2^4} = \dfrac{2\times 2}{2\times 2\times 2 \times 2} = \dfrac{1}{2^2} = 2^{-2} = 2^{2-4}](https://tex.z-dn.net/?f=%20%5Cdfrac%7B2%5E2%7D%7B2%5E4%7D%20%3D%20%5Cdfrac%7B2%5Ctimes%202%7D%7B2%5Ctimes%202%5Ctimes%202%20%5Ctimes%202%7D%20%3D%20%5Cdfrac%7B1%7D%7B2%5E2%7D%20%3D%202%5E%7B-2%7D%20%3D%202%5E%7B2-4%7D%20)
So, everything is coherent
Answer:
37
-----
56
Step-by-step explanation: