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erastovalidia [21]

3 years ago

14

A motorist travels 90 miles at a rate of 20 miles per hour. If he returns the same distance at a rate of 40 miles per hour, what

is the average speed for the entire trip, in miles per hour?

1 answer:

Anna71 [15]3 years ago

7 0

Answer:

The answer is x = 1800

Step-by-step explanation:

Hope this helps :)

Have a nice day.

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Solve the equation 3(4 + 3r)

sertanlavr [38]

The answer is 12+3r because 4 times 3=12 then the 3r which you cannot add because they are no others variables that are r

5 0

3 years ago

Dee Anna has a roast that weighs 5.5 pounds. The recipe she is using calls for a roast that is 80 ounces. How many ounces does s

Maslowich

Answer:

24

Step-by-step explanation:

well yea just trust me :)

6 0

3 years ago

Read 2 more answers

Simplify the expression 2.75j + 2.25 - 1.5j + 3

Katarina [22]

1.25j+5.25 would be the answer. just combine like terms

3 0

3 years ago

Given a trapezoid with a height of 4.3m and bases of 9.2 m and 3.2m, what is the area of the trapezoid? Do not include units in

77julia77 [94]

For a height of 4.3m and bases of 9.2 m and 3.2m, the area of the trapezoid is mathematically given as

A=26.7

<h3>What is the area of the trapezoid?</h3>

Generally, the equation for the trapezoid is mathematically given as

A=0.5*(a+b)*h

Therefore

A=0.5*(3.2+9.2)*4.3

A=26.7

In conclusion,area of the trapezoid

A=26.7

Read more about Arithmetic

brainly.com/question/22568180

7 0

2 years ago

PLEASE I need help on these 4 problems you don’t have to do them all but if you can at least do one of them TYSM

Brrunno [24]

Answer:

For right angle triangle,

we use Pythagoras theorem that is:

$c^{2} =a^{2} +b^{2}$

c = $\sqrt{a^{2} +b^{2} }$

For question 1:

c = ?

a = 40

b = 9

putting them in formula,

c = $\sqrt{40^{2} + 9^{2} }$

c = 41

For question 2:

c = ?

a = 12

b = 13

putting them in formula,

c = $\sqrt{12^{2} + 13^{2} }$

c = approximately 17.69181

For question 3:

c = 35

a = 20

b = ?

putting them in formula,

$c^{2} =a^{2} +b^{2}$

$35^{2} = 20^{2} + b^{2}$

1225 = 400 + $b^{2}$

$b^{2}$ = 1225 - 400

$b^{2}$ = 825

$\sqrt{b^{2} } = \sqrt{825}$

b = 5 $\sqrt{33}$

For question 4:

c = 37

a = 20

b = ?

putting them in formula,

$c^{2} =a^{2} +b^{2}$

$37^{2} = 20^{2} + b^{2}$

1369 = 400 + $b^{2}$

$b^{2}$ = 1369 - 400

$b^{2}$ = 969

Taking square root on both sides

b = 31.12

Hope it helps.

4 0

2 years ago