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Ne4ueva [31]
3 years ago
12

Evaluate the following expression for x = 3 and y = 4: x2 + y 2 =

Mathematics
1 answer:
Colt1911 [192]3 years ago
5 0

Answer:

Step-by-step explanation:

14

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What percent is 27.30 of 36.40 ?
Luden [163]
If you would like to know what percent is 27.30 of 36.40, you can calculate this using the following steps:

x% of 36.40 = 27.30
x/100 * 36.40 = 27.30
x/100 = 27.30/36.40
x = 27.30/36.40 * 100
x = 75

To check: 75% * 36.40 = 75/100 * 36.40 = 27.30

The correct result is 75%. 
7 0
3 years ago
WILL GIVE BRAINLIEST FOR 1 ALGEBRA QUESTION!!!
irinina [24]

Answer:

x=4, y=3

Step-by-step explanation:

6 0
3 years ago
Kenny reads 5/8 page in 2/3 minute. <br><br> This is unit rates
Nat2105 [25]
Find unit rate of pages read per minute:

(5/8)/(2/3)

(5/8)*(3/2)

(5*3)/(8*2)

(15)/(16)

15/16

Kenny reads 15/16 pages every minute (unit rate)
5 0
3 years ago
3x + 5 = x - 3
dusya [7]

Answer:

x = -4

Step-by-step explanation:

3x + 5 = x - 3

Subtract x from each side

3x+5-x = x-3-x

2x+5 = -3

Subtract 5 from each side

2x+5-5 = -3-5

2x = -8

Divide each side by 2

2x/2 = -8/2

x = -4

7 0
3 years ago
Read 2 more answers
A rectangular tank that is 5324 ft cubed with a square base and open top is to be constructed of sheet steel of a given thicknes
marishachu [46]

Answer:

Side of 22 and height of 11

Step-by-step explanation:

Let s be the side of the square base and h be the height of the tank. Since the tank volume is restricted to 5324 ft cubed we have the following equation:

V = s^2h = 5324

h = 5324 / s^2

As the thickness is already defined, we can minimize the weight by minimizing the surface area of the tank

Base area with open top s^2

Side area 4sh

Total surface area A = s^2 + 4sh

We can substitute h = 5324 / s^2

A = s^2 + 4s\frac{5324}{s^2}

A = s^2 + 21296/s

To find the minimum of this function, we can take the first derivative, and set it to 0

A' = 2s - 21296/s^2 = 0

2s = 21296/s^2

s^3 = 10648

s = \sqrt[3]{10648} = 22

h = 5324 / s^2 = 5324 / 22^2 = 11

4 0
3 years ago
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