This is a division problem involving fractions.
57 / (3/4)
57 * (4/3) =
128/3 = 76 pieces of wire
Answer:
<em>A container can hold 473.176 ml</em>
<em>42.52 grams is nitrogen. </em>
Step-by-step explanation:
<u>Part A:</u>
We have given that a container holds 0.500 qt . Now we have to find how many milliliters of lemonade it can hold.
We know that 1 qt = 946.353 ml
To find how many milliliters of lemonade a container hold, we have to convert 0.500qt into ml.
As we have mentioned above that 1 qt = 946.353 ml
Multiply the volume value by 946.353
.
0.500 * 946.353
= 473.176 ml
<em>It means a container can hold 473.176 ml</em>
<u>Part B:</u>
Convert the unit oz to grams. The ratio is 1 ounce is to 28.34 grams.
We have 10.0 oz.
10* 28.34 = 283.495
This would mean 10 oz is equivalent to 283.50 grams. It is given that the fertilizer is 15% by mass nitrogen. It means for every 100 g of fertilizer 15 grams of that is nitrogen. Hence for every 283.50 grams of fertilizer
<em>283.50 * (15/100) = 42.52 grams is nitrogen. </em>
<em></em>
Answer:
14
Step-by-step explanation:
k
=
c
−
b
2
4
a
We know that
a
=
1
,
b
=
−
8
and
c
=
2
, so let's substitute:
k
=
2
−
(
−
8
)
2
4
(
1
)
=
2
−
64
4
=
2
−
16
=
−
14
.
So, we have
min
=
−
14
. Let's check:
graph{(x^2 - 8x + 2 - y)(-14 -y)=0 [-11.82, 20.22, -15.38, 0.64]}
Answer:
a)
y = 0.3035 + 0.0082x
b)
0.6315 mm
c)
x = 23.9634 °C
Step-by-step explanation:
a. Compute the least-squares line for predicting warping from temperature. Round the answers to four decimal places.
We need to find an equation of the form
y = b + mx
where m is the slope and b the Y-intercept.
The slope m can be computed with the formula
Replacing the values in our formula (we will round at the end of the calculations)
the Y-intercept b is computed with the formula
therefore we have
and the least-squares line rounded to 4 decimals would be
y = 0.3035 + 0.0082x
b. Predict the warping at a temperature of 40°C. Round the answer to three decimal places.
We simply replace x with 40 to get
y = 0.3035 + 0.0082*40 = 0.6315 mm
c. At what temperature will we predict the warping to be 0.5 mm? Round the answer to two decimal places
Here, we replace y with 0.5 and solve for x
0.5 = 0.3035 + 0.0082x ===> x = (0.5-0.3035)/0.0082 ===>
x = 23.9634 °C
Answer:
is there a diagram?
Step-by-step explanation: