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scoray [572]
2 years ago
13

I have a challenge. All of you that read this, comment or make an answer. After you are done, do the same thing! Make a free bra

inliest and the first person that answers gets it. And thank the person by going to their profile! Whoever answers this first gets brainliest!
Mathematics
2 answers:
Tresset [83]2 years ago
7 0

seems pretty odd but I guess there's nothing else to do during quarantine

padilas [110]2 years ago
5 0

Answer:

ok

Step-by-step explanation:

You might be interested in
Good Morning everyone! I need help please! :) First gets Brainliest
kicyunya [14]

Answer:

C. The distribution for town A is positively skewed, but the distribution for town B is symmetric.

Hope it helps you out!

5 0
3 years ago
Consider the line y=-5/9x+6
Arlecino [84]

Answer:

See below in bold.

Step-by-step explanation:

Use the point-slope form of a straight line

y - y1 = m(x - x1)

Here m = -5/9 , x1 = 9 and y1 = -3:, so

y - -3 = -5/9(x - 9)

y + 3 = -5/9x + 5

y = -5/9x + 2  is the equation parallel to the given line.

The  line perpendicular to the given line will have a slope of - 1 / -5/9

= 9/5 so its equation is

y  + 3 = 9/5(x - 9)

y = 9/5x - 81/5 - 3

y = 9/5x - 96/5 .

4 0
2 years ago
Find mZ3 if mZ5 = 145º and mZ4 = 45°
trapecia [35]

9514 1404 393

Answer:

  C.  100°

Step-by-step explanation:

The exterior angle is equal to the sum of the remote interior angles.

  ∠5 = ∠3 +∠4

  145° = ∠3 +45° . . . . fill in the given values

  100° = ∠3 . . . . . . subtract 45° from both sides

7 0
2 years ago
Which function is most likely graphed on the coordinate plane below?<br> y у
Sindrei [870]

Answer:b

Step-by-step explanation:

i took it

7 0
2 years ago
I need some help with these in kinda like a essay form
WINSTONCH [101]

A. The amount (A) at the end of t years of continuous compounding of principal P at rate r will be

... A = Pe^(rt)

For P=1000, r=.02, and t=1, The amount is

... A = $1000e^(.02·1) = $1020.20134

B. The formula for daily compounding is

... A = P(1 + r/365)^(365t)

Using the same values of P, r, t, the amount is

... A = $1000(1 +.02/365)^365 = $1020.20078

Continuous compounding produces a larger result.

The result gets larger the more often compounding occurs. Continuous compounding is the highest possible rate at which compounding can take place, so produces the largest possible result.

C. The balance at the end of the year when interest is compounded n times per year is given by

... A = P(1 + r/n)^n

Each year interest is compounded this way, the amount is multiplied by

... (1 + r/n)^n

When this happens each year for t years, the multiplier has been applied t times. Exponentiation is used to represent the effect of such repeated multiplication, so the balance at the end of t years is

... A = P((1 + r/n)^n)^t = P(1 +r/n)^(nt)

D. (Note the previous answer assumed the existence of this answer.) The same logic as for C above applies for each period that compounding takes place. That is, if compounding occurs n times per year, the interest rate applied for each period is the nominal annual rate r divided by the number of periods n. The multiplier applied to the initial principal amount is

... (1 + r/n)

When than factor is used n times during the year, the multiplier of the initial principal amount is

... (1 + r/n)·(1 + r/n)· ... ·(1 + r/n) . . . where the factor is applied n times.

In more compact notation, this multiplier is

... (1 +r/n)^n

When that multiplier is applied to principal P, the account balance A at the end of the year is ...

... A = P(1 +r/n)^n

7 0
3 years ago
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